A number with a zero in the ten's place needs to be at least a 3-digit number
So such a number can be 301, where 1 is at the unit's place, 0 is at the ten's place, and 3 is at the hundred's place
Please look at the image for reference.
Answer:
so puit your years in the fist colum it will look like this
Years Josiah Tillery
1 13 8
2 16 11
3 19 14
4 22 17
5 25 20
and i do believe it is proportional because they are even no matter what
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Given:</u>
- f(x) = x/2 - 3
- g(x) = 4x² + x - 4
<u>Find (f + g)(x):</u>
- (f + g)(x) =
- f(x) + g(x) =
- x/2 - 3 + 4x² + x - 4 =
- 4x² + 3x/2 - 7
Correct choice is C
Answer:
ok
x = 2+3×-×/2
f ×6 = 143.576÷ 0 67-5486u7u6857+/_475