The shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet
<h3>What dimensions would guarantee that the garden has the greatest possible area?</h3>
The given parameter is
Perimeter, P = 520 feet
Represent the shorter side with x and the longer side with y
One side of the garden is bordered by a river:
So the perimeter is:
P = 2x + y
Substitute P = 520
2x + y = 520
Make y the subject
y = 520 - 2x
The area is
A = xy
Substitute y = 520 - 2x in A = xy
A = x(520 - 2x)
Expand
A = 520x - 2x^2
Differentiate
A' = 520 - 4x
Set to 0
520 - 4x = 0
Rewrite as:
4x= 520
Divide by 4
x= 130
Substitute x= 130 in y = 520 - 2x
y = 520 - 2 *130
Evaluate
y = 260
The area is then calculated as:
A = xy
This gives
A = 130 * 260
Evaluate
A = 33800
Hence, the shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet
Read more about area at:
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You can double the product of 9 and 4 to get to the product of 9 and 8
Answer:
Simple...
you have: x-3y=18
You want to convert it into slope-intercept form or y=mx+b form-->>>
x-3y=18
Isolate the variable-->>
x-3y=18
-x -x
-3y=-x+18
Now simply divide...
-3y/-3 = -x+18/-3
y=1/3x=6
Thus, your answer.
If she cut off nine pieces of 2-inch ribbon, in all, that would be 18. After that, it would simply be the matter of subtracting 24 and 18.
24 - 18 = 6.
And there's your answer. Liz has 6 inches of ribbon left.