3 years ago

Help please I need these answers

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

8 0

Answer:

bro i cant see take another pic

Step-by-step explanation:

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oouu I'm in 7th grade science and I already did this I can help!

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3 years ago

What is the solution of the following system?

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Answer:

The answer to your question is: both lines are the same.

Step-by-step explanation:

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Elimination method

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3 years ago

Help me out please?<br>chapter : exponents and powers

belka [17]

Answer:

$\frac{125}{27}$

Step-by-step explanation:

$\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}$

Lets expand all the composite numbers into prime numbers.

$=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}$

Lets cancel $2^{-4}$ from numerator and denominator.

$=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}$

Using laws of exponents , lets solve this.

$=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}$

$=> \frac{3^{-3} \times 5^{1}}{5^{-2}}$

$=> 3^{-3} \times 5^{[1 - (-2)]}$

$=> 3^{-3} \times 5^{3}$

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