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3 years ago

30g of sugar is needed to make 4 cakes. How much sugar is needed to makes 7 cakes

Mathematics

1 answer:

Yanka [14]3 years ago

3 0

there are many ways to solve with ratios between sugar and number of cakes, idk if you know how to do that, but any way you do it the correct answer is 52.5g

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Can someone help me with this If 5y*2=80 y=?

Temka [501]

If 5y*2=80 then y is equal to 8

8 0

3 years ago

Read 2 more answers

If nine times a certain number is subtracted from 7 the result is 52. Find the number.

mezya [45]

Answer:

Let the number to find be x

7 - 9x = 52

-9x = 52-7

- 9x = -45

Divide by - 9

x = 5

The number is 5

Hope this helps.

6 0

4 years ago

Read 2 more answers

Your friend, Susannah, manages a sandwich shop. She collects data on the number of turkey sandwiches sold per day for a week. Ex

ExtremeBDS [4]

Susannah's data are illustration of measure of central tendencies

(a) The mean

To calculate the mean, she needs to divide the total number of turkey sandwiches sold, by the number of days.

The total is:

$\mathbf{Total = 73 +88+85+88+99+134+129}$

$\mathbf{Total = 696}$

The number of days is:

$\mathbf{Day = 7}$

So, the mean is:

$\mathbf{Mean =\frac{Total}{Days}}$

$\mathbf{Mean =\frac{696}{7}}$

$\mathbf{Mean =99.4}$

Hence, the mean number of turkey sandwiches sold is 99.4

(b) The median

To calculate the median, she needs to arrange the data in ascending or descending order, then select the middle item.

In ascending order, we have: 73, 85, 88, 88, 99, 129, 134

The middle item is 88

So:

$\mathbf{Median = 88}$

Hence, the median number of turkey sandwiches sold is 88

(c) The mode

This is the data that occurs most.

From the dataset, 88 appears twice (more than others).

So:

$\mathbf{Mode = 88}$

Hence, the mode number of turkey sandwiches sold is 88

(d) The range

This is the difference between the highest and least data

From the dataset,

The highest is 134, and the least is 73

So:

$\mathbf{Range =134 - 73}$

$\mathbf{Range =61}$

Hence, the range of turkey sandwiches sold is 61

The measure that would be most helpful is the median, because it is not affected by outliers.

Read more about measures of central tendencies at:

brainly.com/question/5495004

6 0

3 years ago

How does the graph of f(x) = (x + 2)4 + 6 compare to the parent function g(x) = x4?

Alchen [17]

Answer: find the answer in the explanation

Step-by-step explanation:

Given that the transformed graph is of function f(x) = (x + 2)^4 + 6 and the parent function g(x) = x^4

The transformed graph function g(x) was shifted two (2) units to the left and was translated six (6) units upward.

When the function is shifted to the right, the factor of x will be negative and when it's shifted to the left, the factor of x will be positive.

Therefore, function g(x) = x^4 is shifted 2 units to the left and translated 6 units upward to form f(x) = ( x + 2 )^4 + 6.

5 0

3 years ago

A nonprofit organization sent mailing labels along with a request for donations to a random sample of 75,000 potential donors on

Law Incorporation [45]

Answer:

Check the explanation

Step-by-step explanation:

The null and alternative hypotheses in symbols and words are as follows:

: p ≤ 0.06 (There has been no change in the contribution rate due to addition of the mailing labels)

: p > 0.06 (The addition of the mailing labels has increased the contribution rate)

Test Statistics

The following information is provided: The sample size is N = 75000, the number of favorable cases is X = 5625, and the sample

The z-statistic is computed as follows:

- $P_0$ (1 -

Test statistic z = 17.297

P-value

P-value corresponding to z = 17.297 for a two tailed test is obtained using standard normal table.

p-value = 0.0000

90% Confidence Interval Calculation

Kindly check the attached image below.

Conclusion

Since p-value = 0.0000 < α = 0.05, we reject null hypothesis .

At 0.05 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.

Since the 90% confidence interval (0.073, 0.077) does not contain the hypothesized value 0.06, the result is significant and we reject null hypothesis.

In other words, at 0.10 significance level, there is enough evidence to conclude that the addition of the mailing labels has increased the contribution rate.

4 0

4 years ago