Question

What are the domain and range of the function f(x)=(√x-7)+9?

Answer 1

Answer:

the domain of the function f(x) is $x\ge 7$

the range of the function f(x) is $f(x)\ge 9$

Step-by-step explanation:

Consider the parent function $y=\sqrt{x}.$

The domain og this function is $x\ge 0,$ the range of this function is $y\ge 0.$

The function $f(x)=\sqrt{x-7}+9$ is translated function $y=\sqrt{x}$ 7 units to the right and 9 units up, so

the domain of the function f(x) is $x\ge 7$

the range of the function f(x) is $f(x)\ge 9$