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Umnica [9.8K]
3 years ago
8

I need help with 4 and 5 please

Mathematics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

C

Step-by-step explanation:

to find 4, you use the equation a^{2}+b^{2}=c^{2} where the c= hypotenuse, which is the slant of the triangle. Then you width and length can by put as a and b. This gives you 15^{2}+4^{2} = s^{2}. Then you solve for s which end up being 15.5.

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What is the value of |n|=5
nikdorinn [45]

Answer:

n = 5 or -5

Step-by-step explanation:

the absolute value is the count away from 0 so n could be 5 which is 5 units from 0 or -5 which is also 5 units away from 0.

7 0
3 years ago
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If these two shapes are similar, what is the measure of the missing length z?
netineya [11]

Answer:

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7 0
3 years ago
What is the medium lower quartile upper quartile and interquartil of the numbers
docker41 [41]
First you find the median, by taking 893+954 and dividing the sum of those two numbers by 2. The median is 923.5. Then you take and find the median of the numbers before the median which is 513. That is your lower quartile. Then you find the median of the numbers below the median, which is 1038. That is your upper quartile. The interquartile range is your upper quartile minus your lower quartile.  

Therefore, your answer would be: 
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Upper Quartile- 1038
Interquartile Range- 525

3 0
3 years ago
0.8b = 1.12<br><br><br><br><br><br>HELP please please
timama [110]
B=1.4
Is the answer. 

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5 0
3 years ago
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the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2
Ksivusya [100]

Answer:

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1.

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is \frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1.

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,  

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by b^{2} = a^{2}(e^{2}  - 1) = 4[(\frac{5}{2} )^{2} -1] = 21 {Since e = \frac{5}{2} given}

Therefore, the equation of the given hyperbola will be  

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1. (Answer)

6 0
3 years ago
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