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Umnica [9.8K]
2 years ago
8

I need help with 4 and 5 please

Mathematics
1 answer:
Tamiku [17]2 years ago
3 0

Answer:

C

Step-by-step explanation:

to find 4, you use the equation a^{2}+b^{2}=c^{2} where the c= hypotenuse, which is the slant of the triangle. Then you width and length can by put as a and b. This gives you 15^{2}+4^{2} = s^{2}. Then you solve for s which end up being 15.5.

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The mean is \sqrt{3}.

Step-by-step explanation:

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Wang Yong owes the bank \$8500$8500dollar sign, 8500. To repay the debt, he paid a fixed amount back to the bank each month. Aft
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Complete question :

Wang Yong owes the bank $8500. To repay the debt, he paid a fixed amount back to the bank each month. After 12 months, his remaining debt was $6460. How much did Wang Yong pay each month?

Answer:

$170

Step-by-step explanation:

Given that:

Amount owed = $8500

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8 0
3 years ago
A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a
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Answer:

407 mi/h

Step-by-step explanation:

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Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, s=\frac{dx}{dt}=470\ mi/h

Now, applying Pythagoras theorem to the triangle, we have:

D^2=h^2+x^2\\\\D^2=1+x^2

Differentiating with respect to time 't', we get:

2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi

Now, plug in all the given values and solve for \frac{dD}{dt}. This gives,

\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

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The temperature in Moscow, Russia at 8:00 A.M. is 6 degrees
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Answer:

0 degrees

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