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zimovet [89]
3 years ago
11

Sec(x)-tan(x)=1/sec(x)+tan(x)

Mathematics
1 answer:
Rama09 [41]3 years ago
3 0

Answer:

Step-by-step explanation:

I assume that you mean

sec(x)-tan(x) = 1 / ( sec(x) + tan(x) ) , right ?

then this is equivalent to

[ sec(x) - tan(x) ] x [ sec(x) + tan(x) ] = 1

let s evaluate it, we got

sec2(x) - sec(x)tan(x) + - sec(x)tan(x) - tan2(x) = sec2(x) - tan2(x)

= (1 - sin2(x) ) / cos2(x) = cos2(x) / cos2(x) = 1

as cos2(x) + sin2(x) = 1

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Yuki888 [10]

For this case we must find the slope of the following equation:

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By definition, the point-slope equation of a line is given by:

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Where:

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So, the slope of the given equation is:

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Answer:

Option D

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<em>y=2 is the correct answer.</em>

<em>2 is the correct answer.</em>

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