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zimovet [89]
3 years ago
11

Sec(x)-tan(x)=1/sec(x)+tan(x)

Mathematics
1 answer:
Rama09 [41]3 years ago
3 0

Answer:

Step-by-step explanation:

I assume that you mean

sec(x)-tan(x) = 1 / ( sec(x) + tan(x) ) , right ?

then this is equivalent to

[ sec(x) - tan(x) ] x [ sec(x) + tan(x) ] = 1

let s evaluate it, we got

sec2(x) - sec(x)tan(x) + - sec(x)tan(x) - tan2(x) = sec2(x) - tan2(x)

= (1 - sin2(x) ) / cos2(x) = cos2(x) / cos2(x) = 1

as cos2(x) + sin2(x) = 1

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Simplify <br><br> 5cat + 3act - 6tac
djverab [1.8K]

Answer:

the correct answer is 2 act

Step-by-step explanation:

there is same base (act)

then 5+3=8

and 8-6 = 2act

7 0
2 years ago
Which of the following is the reciprocal of the factored form of: x2 - 2x - 8
Olegator [25]

We are given quadratic x^2-2x-8.

Let us factor it by product sum rule.

According to product sum rule, we need to find the factors of -8 that add upto -2.

If we write all factors of 8, we get 8,4,2 and 1 factores.

So, we could choose -4 and +2.

Because -4+2 = -2 (sum) and -4*2=-8 (product)

x^2-2x-8

Splitting middle term into two terms -4x+2x

x^2-4x+2x−8

Factoring out gcf from each group.

x(x-4) +2(x- 4)

(x + 2)(x - 4)

So, we got factored form of the given euadratic (x + 2)(x - 4).

Reciprocal of it would be \frac{1}{(x+2)(x-4)}.


8 0
3 years ago
Read 2 more answers
7.97 as a mixed fraction and a improper fraction
4vir4ik [10]

Answer:

7 97/100

797/100

Step-by-step explanation:

6 0
3 years ago
Find the center, vertices, and foci of the ellipse with equation 3x2 + 8y2 = 24
Sveta_85 [38]

Answer:

The center is at (0,0)

The vertices are at ( ( ±2 sqrt(2),0)

foci are  ( ±sqrt(5),0)

Step-by-step explanation:

3x^2 + 8y^2 = 24

Divide each side by 24

3x^2 /24 + 8y^2/24 = 24/24

x^2/8  + y^2 /3 = 1

The general equation of an ellipse is

(x-h)^2/  a^2  + (y-k)^2 / b^2  = 1

a>b   (h,k) is the center

the coordinates of the vertices are ( ±a,0)

the coordinates of the foci are  ( ±c,0), where  ^c2=a^2−b^ 2

The center is at (0,0)

a = sqrt(8) = 2sqrt(2)

The vertices are at ( ( ±2 sqrt(2),0)

c = 8 - 3 =5

foci are  ( ±sqrt(5),0)

3 0
4 years ago
Read 2 more answers
Any answers? im bit stuck on this
Aleks04 [339]

Step-by-step explanation:

The vertical angles are congruent. The right angles are congruent. There are 2 angles of a triangle congruent to 2 angles of anther triangle. By AA Similarity the triangles are similar.

Statement A. (vertical angles are congruent)

Statement D. (right angles are congruent)

Triangle AEC is similar to triangle BDC.

Statement E is true but does not help.

Correct statement of proportional side lengths:

BD/AE = CD/CE

x/150 = 200/50

x/150 = 4

x = 600

P.S. I think there is a mistake in the problem. I don't think that statement E is correct. It is a true statement, but it is useless. Statement F is false.

6 0
3 years ago
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