The answer should be option D.
Because natural number can be negative .
If graph of the function y=f(x) was shifted to the right 1 unit, then you got new function y=f(x-1).
Reversly, if you have the function

that is obtained by shifting to the right 1 unit, then the initial function was

.
Answer: Correct choice is D.
Assuming you mean f(t) = g(t) × h(t), notice that
f(t) = g(t) × h(t) = cos(t) sin(t) = 1/2 sin(2t)
Then the difference quotient of f is

Recall the angle sum identity for sine:
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
Then we can write the difference quotient as

or

(As a bonus, notice that as h approaches 0, we have (cos(2h) - 1)/(2h) → 0 and sin(2h)/(2h) → 1, so we recover the derivative of f(t) as cos(2t).)
Answer:
idk
Step-by-step explanation:
Answer:
1
Step-by-step explanation: