Question

Answers in Scientific Notation.

Answer 1

one way is to factor the expressions

(a)

$10^{5}$ (1.2 + (5.35 × $10^{1}$))

= $10^{5}$ (1.2 + 53.5)

= 54.7 × $10^{5}$ = 5.47 × $10^{1}$× $10^{5}$ = 5.47 × $10^{6}$

(b)

$10^{-3}$((6.91 × $10^{1}$) + 2.4)

= $10^{-3}$(69.1 + 2.4)

= 71.5 × $10^{-3}$ = 7.15 × $10^{1}$ × $10^{-3}$ = 7.15 × $10^{-2}$

(c)

$10^{5}$((9.7 × $10^{1}$) + 8.3)

= $10^{5}$(97 + 8.3)

= 105.3 × $10^{5}$ = 1.053 × $10^{2}$ × $10^{5}$ = 1.053 × $10^{7}$

(d)

$10^{1}$((3.67 × $10^{1}$) - 1.6)

= $10^{1}$(36.7 - 1.6)

= 35.1 × $10^{1}$ = 3.51 × $10^{1}$ × $10^{1}$ = 3.51 × $10^{2}$

(e)

$10^{-6}$((8.41 × $10^{1}$) - 7.9)

= $10^{-6}$(84.1 - 7.9 )

= 76.2 × $10^{-6}$ = 7.62 × $10^{1}$ × $10^{-6}$ = 7.62 × $10^{-5}$

(f)

$10^{4}$((1.33 × $10^{1}$) - 4.9 )

= $10^{4}$(13.3 - 4.9) = 8.4 × $10^{4}$