Solve the system (x-1)²+(y-2)²=2² and y=2x+2.
1 answer:
Answer:
(x, y) = (-0.6, 0.8) or (1, 4)
Step-by-step explanation:
Use the second equation to substitute for y in the first.
(x -1)² +((2x +2) -2)² = 4
x -2x +1 + 4x² = 4 . . . . . . . eliminate parentheses
5x² -2x -3 = 0 . . . . . . . . . . subtract 4, collect terms
Now we can rearrange the middle term to ease factoring by grouping.
(5x² -5x) +(3x -3) = 0
5x(x -1) +3(x -1) = 0
(5x +3)(x -1) = 0
The values of x that make these factors zero are ...
x = -3/5, x = 1
The corresponding values of y are ...
y = 2(-3/5)+2 = 4/5 . . . . for x = -3/5
y = 2(1) +2 = 4 . . . . . . . . for x = 1
The solutions are: (x, y) = (-3/5, 4/5) or (1, 4).
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A graphing calculator verifies these solutions.
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Answer:
(-2, -4)
Step-by-step explanation:
Given:
The system of equations to solve is given as:
In order to solve this system of linear equations, we use substitution method.
In substitution method, we substitute the value of any one variable in the other equation.
So, we substitute the value of 'y' from first equation in the second equation.
This gives,
Dividing both sides by 3, we get:
Now,
Therefore, the solution is (-2, -4)