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nadezda [96]
3 years ago
14

A circle is centered at the vertex of an angle, and the angle's rays subtend an arc that is 86 cm long. 1/360th of the circumfer

ence of the circle is 0.5 cm long. What is the measure of this angle in degrees?
Mathematics
2 answers:
rewona [7]3 years ago
6 0

Answer:

Therefore the measure of this angle is =(\frac{43}{90} )^\circ

Step-by-step explanation:

Given, a circle is centered at the vertex of an angle  and the angle's rays subtend an arc that is 86 cm long.

0.5 cm arc make an angle \frac{1}{360}

1 cm arc make an angle \frac{1}{360\times 0.5}

86 cm arc make an angle \frac{86}{360\times 0.5}

                                         =(\frac{43}{90} )^\circ

Therefore the measure of this angle is =(\frac{43}{90} )^\circ

nataly862011 [7]3 years ago
3 0

Answer:

its 4.5 if u have the usa test prep one

Step-by-step explanation:

i just did it and its correct :)

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In the figure below, C is between A and D, and B is the midpoint of AC. If BD=8 and BC=6, find AD.
ANEK [815]

Answer:

AD = 14

Step-by-step explanation:

BC = 6

BD = 8

CD = BD - BC

CD = 8 - 6

CD = 2

Since B is the midpoint of AC, therefore:

AC = 2*BC

AC = 2*6

AC = 12

Thus:

AD = AC + CD

AD = 12 + 2

AD = 14

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2 years ago
Choose the equation below that represents the line passing through the point (−3, −1) with a slope of 4.
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Y = 4(-3) + 11
y = -12+11
y= -1

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3 years ago
Use the data to create a scatter plot.
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I'm not sure about the given data but I plotted the scatter plot based on what I understand on how the data should be presented.

Time (years)
3, 6, 9, 12, 15, 18, 21, 24

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22, 25, 28, 14, 17, 20,15, 9

Attached is the scatter plot created online.
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3 years ago
The manager at a sports radio station will be covering several football games over the weekend. She knows that most of her liste
Paraphin [41]

Complete Question:

The manager at a sports radio station will be covering several football games over the weekend. She knows that most of her listeners are at least 22 years old and wants to know what age group she should gear her advertisements to for the games. She takes a random sample of 46 listeners from age 22-39 and 57 listeners who are 40 and older and asks them if they are likely to tune in to football games. The "yes" responses are recorded in the file attached below.

1. At the 0.05 level of significance, is there a significant difference in the proportion of listeners based on age?

2. Is there evidence to suggest that there is a significant difference in the proportion of listeners based on age?

Answer:

1) There is no significant difference in the proportion of listeners based on age

2) No, there is no evidence

Step-by-step explanation:

Sample size of group 1, n_1 = 46

Sample size of group 2, n_2 = 57

Number of Yes in group 1,  X_1 = 32

Number of Yes in group 2, X_2 = 47

Proportion of Yes in group 1:

\hat{p_1} = \frac{X_1}{n_1} \\\hat{p_1} = \frac{32}{46}\\\hat{p_1} = 0.6957

Proportion of Yes in group 2:

\hat{p_2} = \frac{X_2}{n_2} \\\hat{p_2} = \frac{47}{57}\\\hat{p_2} = 0.8246

Null Hypothesis, H_0: p_1 = p_2

Alternate Hypothesis,H_a: p_1 \neq p_2

\hat{p} = \frac{X_1 + X_2}{n_1 + n_2}  \\\\\hat{p} = \frac{ 32+47}{46+57} \\\\\hat{p}= 0.767

Significance level,

Calculate the test statistic

z = (\hat{p_1} - \hat{p_2})/\sqrt{(\hat{p} * (1-\hat{p}) * (\frac{1}{N_1}  + \frac{1}{N_2})}\\\\z = (0.6957-0.8246)/ \sqrt{(0.767*(1-0.767)*(1/46 + 1/57))}\\\\z = -1.54

Get the P-value from the probability distribution table:

At z = -1.54, P-value = 0.1236

Since (P-value = 0.1236) > (α = 0.05), we will accept the null hypothesis. This means that there is no evidence to suggest that there is difference in the proportion of listeners based on age.

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