Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Step-by-step explanation:
I've shown the process in the picture.
hope u understand
Answer: If the height is doubled the volume becomes a bigger number so 3 times 2 is 6 and 4 times 2 is 8 then 5 times 2 is 10. 6+8+10=24
Step-by-step explanation:
Answer:
The final price will be $12.67
Step-by-step explanation:
Discount = Original Price x Discount %/100
Discount = 14.9 × 15/100
Discount = 14.9 x 0.15
You save = $2.24
Final Price = Original Price - Discount
Final Price = 14.9 - 2.235
Final Price = $12.67
hope this helps and is right. p.s. i really need brainliest :)
Answer:
j^-1(x) = 1/2(x+5)
Step-by-step explanation:
1. Replace j(x) with y to make it easier
y = 2x - 5
2. Switch the places of x and y
x = 2y - 5
3. Solve for y
x + 5 = 2y
y = 1/2(x+5)
4. Replace y with j^-1(x)
j^-1(x) = 1/2(x+5)
