When PbSO₄ is added it dissociates as follows
PbSO₄ --> Pb²⁺ + SO₄²⁻
molar solubility is the number of moles of solute that can be dissolved in 1 L of solution
if molar solubility of PbSO₄ is X, then molar solubility of Pb²⁺ is X and SO₄²⁻ is X
the formula for ksp is as follows
ksp - solubility product constant
ksp = [Pb²⁺][SO₄²⁻]
ksp = X * X
ksp = X²
ksp = 1.82 x 10⁻⁸
X² = 1.82 x 10⁻⁸
X = 1.35 x 10⁻⁴ M
molar solubility of PbSO₄ is 1.35 x 10⁻⁴ M
answer is b.
Answer:
[Ar]4s²
Explanation:
The electronic configuration of calcium is given as follows;
1s²2s²2p⁶3s²3p⁶4s²
The electronic configuration of argon, Ar is 1s²2s²2p⁶3s²3p⁶
Given, that there is a similarity be tween the electronic configuration of all the shells of the an atoms of argon and an atom calcium, except for the added valence shell electrons in calcium, the electronic configuration of calcium can be represented by the symbol of an atom of argon, followed by the electonic configuration of the valence shell as follows
The electronic configuration of calcium with argon as base = [Ar]4s².
Answer:
FALSE
Explanation:
Sedimentary rocks are defined as those rocks that are formed due to the combined effect of compaction and cementation process. In order to form sedimentary rocks, at first, the sediments that are transported from other places must be deposited. This deposited sediments over a due course of time, are subjected to high compaction due to the weight of the overlying weight. This results in the transformation of loose sediments into hard rocks. This how sedimentary rocks are formed which are comprised of sand-size particles. For example, Shale, Sandstone, and Mudstone.
Thus, both the compaction and cementation processes are important for the formation of sedimentary rocks.
Hence, the above-given statement is False.
Hey there!
Si₂H₃ + O₂ → SiO₂ + H₂O
Balance H.
3 on the left, 2 on the right. Add a coefficient of 2 in front of Si₂H₃ and a coefficient of 3 in front of H₂O.
2Si₂H₃ + O₂ → SiO₂ + 3H₂O
Balance Si.
4 on the left, 1 on the right. Add a coefficient of 4 in front of SiO₂.
2Si₂H₃ + O₂ → 4SiO₂ + 3H₂O
Balance O.
2 on the left, 11 on the right. We can't do this by simply adding coefficients to O₂ since 11 isn't divisible by 2. So we need to multiply the coefficients in front of everything else by 2 first.
4Si₂H₃ + O₂ → 8SiO₂ + 6H₂O
Now we can balance O properly.
2 on the left, 22 on the right. Add a coefficient of 11 in front of O₂.
4Si₂H₃ + 11O₂ → 8SiO₂ + 6H₂O
This is our final balanced equation:
4Si₂H₃ + 11O₂ → 8SiO₂ + 6H₂O
This means the coefficient for O₂ when the chemical equation is balanced is 11.
Hope this helps!