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Natalija [7]
3 years ago
8

at the space center, karen bought a model of a shuttle. She started working on the model the next day at 11:11 A.M. She worked u

ntil leaving for lunch at 11:51 A.M. After lunch, she worked on the model again from 1:29 P.M. until 1:48 P.M. How long did Karen work on the model?
Mathematics
1 answer:
bekas [8.4K]3 years ago
7 0


51-11=40 minutes

48-29=19

40+19= 59 minutes

I hope that helped. :)

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An equilateral triangle with side length 7 cm is shown in the diagram, work out the area of the triangle.
ElenaW [278]
If a triangle has sides of 7 cm and it is an equilateral you can draw a line right down the middle to form two congruent triangles.

These smaller triangles have a hypotenuse of 7cm and a base of 3.5 cm (7/2)

To work out the height, use Pythagoras’ theorem.

a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the other two sides

7^2 - 3.5^2 = 36.75

Square root answer

= 6.06 cm

That’s the height of the triangle

Area of a triangle is base x height divided by 2

So 7 x 6.06 = 42.43…

/2

= 21.2 cm^2 to one d.p

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3 years ago
Tamsen pays $12.50 of her monthly life insurance premium, and her
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Benefit she gets monthly is = 42.25-12.5= 29.75

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3 years ago
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nataly862011 [7]

Answer:

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3 years ago
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If t = 18 and r = 12, find S. Round to the nearest tenth.
choli [55]

Answer: <em>S</em> ≈ 48.2°

Step-by-step explanation:

   We can use trigonometry functions to solve.

   Looking at angle <em>S</em>, t = 18 is the hypotenuse and r = 12 is the adjacent side. This means we can use the cosine function.

   \displaystyle cos(S) =  \frac{\text{adjacent side}}{\text{hypotenuse }}=\frac{12}{18}

  \displaystyle cos^{-1} (cos(S)) =  (\frac{\text{adjacent side}}{\text{hypotenuse }}=\frac{12}{18})cos^{-1}

  S = 48.189685...\\S  \;$\approx$\; 48.2^{\circ}

3 0
2 years ago
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kherson [118]

Answer: 40

Step-by-step explanation:

138/x = 207/60

8280 = 207x

divide by 207

40 = x

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3 years ago
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