Question

Help, please!

Answer 1

Answer:

sin m∠B = square root of 5 over 5

Step-by-step explanation:

You are right B is the answer

Answer 2

Answer:

$\huge\boxed{\sf Option \ B}$

Step-by-step explanation:

In the given triangle:

Opposite to B = 3

Adjacent to B = 6

Hypotenuse = $\sf 3\sqrt{5}$

We'll use the following trigonometric ratio:

$\sf sin \theta = \frac{opposite }{hypotenuse} \\\\sin \ B = \frac{3}{3\sqrt{5} } \\\\sin \ B = \frac{1}{\sqrt{5} } \\\\Multiplying \ both \ numerator \ and \ denominator \ by \ \sqrt{5} \\\\sin \ B = \frac{\sqrt{5} }{\sqrt{5} * \sqrt{5} } \\\\\boxed{\sf sin \ B = \frac{\sqrt{5} }{5} }$

$\rule[225]{225}{2}$

Hope this helped!

~AnonymousHelper1807