3*9-5=22 43*9-5=382 543*9-5=4882 6543*9-5=58882
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Answer:
Step-by-step explanation:
Given that 10000 times a fair coin is flipped. Since fair coin prob for head of tail =0.5
If tail comes it will be taken as 1. Hence for the sum to be less than 5000, no of heads <5000
Since trials are large we approximate to normal with mean = np = 5000 and variance = np(1-p) = 2500
Thus no of heads x is normal with (5000, 50)
Since this prob is less than 0.5 only minimum amount to be bet i.e. 1 dollar
If sum of coins <5100, then Z =
P(Z<2) = 0.9500
This time we can bet maximum of 100 dollars as probability is very high nearer to 1.