1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alisiya [41]
3 years ago
15

A rectangular garden that measures 6 feet by 8 feet is roped off to form a

Mathematics
1 answer:
Feliz [49]3 years ago
8 0

Answer:

10feet

Step-by-step explanation:

We solve this question, using Pythagoras Theorem to solve for the other side.

Pythagoras Theorem states that

c² = a² + b²

c = √(a² + b²)

In the question, a = 6 feet

b = 8 feet

c = length of the rope

c = √6² + 8²

c = √36 + 64

c = √100

c = 10 feet

The length of the rope is 10 feet

You might be interested in
Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters
Mumz [18]

The various answers to the question are:

  • To answer 90% of calls instantly, the organization needs four extension lines.
  • The average number of extension lines that will be busy is Four
  • For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

a)

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$

Generally, the equation for is  mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

b)

The probability that a call will receive a busy signal if four extensions lines are used is,

P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$

Therefore, the average number of extension lines that will be busy is Four

c)

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about extension lines

brainly.com/question/13362603

#SPJ1

8 0
1 year ago
Find the difference and express the answer in Scientific Notation
fenix001 [56]
The correct answer is C. 
this is because 452.7*10^3=452700
and 2.7*10^5=270000
452700-270000=182700
which when expressed in scientific notation is 1.827*105
Hope I was helpful

5 0
2 years ago
Can someone help, please
Jet001 [13]

Answer: 5/1 or just 5

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
Can you help me please? I would appreciate it ❤️❤️
lianna [129]
The answer is 9
You divide 143 % 11 to get 13. 13 is the number they make an hour, so if you divide 117 % 13 you will get 9.
8 0
2 years ago
Nancy needs 4/5 of a foot of ribbon to make a bow and she has 4 feet ribbon how many bows can she make
vlabodo [156]

Answer:

I believe she can make one bow

Step-by-step explanation:

Iso if she has 5 feet of ribbon and only takes four feet of it then that leaves one foot left but if she has a perfect four foot then she can make a ribbon without extra

5 0
3 years ago
Other questions:
  • You are making a necklace that is 9 inches long. You use 6 beads for each inch. What integer is the change in your supply of bea
    14·1 answer
  • Which shape can be classified as a rectangle? Rhombus Square Trapezoid Parallelogram (1 answer choice)
    11·2 answers
  • How do I solve for the variables r,s, and t
    7·1 answer
  • A 25 lb. bag Balkfoods Small Red Beans cost $52.92. What is the unit price<br> per Ib?
    7·1 answer
  • Select all points that lie on line y = 8x - 5
    6·1 answer
  • Find the slope of the line through the given points.<br> (-3,1), (-1,5)
    10·1 answer
  • Question 3(Multiple Choice Worth 2 points)
    12·1 answer
  • Choose the expression that is NOT equivalent to the following expression:
    13·1 answer
  • Two processes in a manufacturing line are performed manually: operation A and operation B. A random sample of 50 different assem
    6·1 answer
  • What is the HCF of two consecutive odd numbers? for 50 points​
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!