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2 years ago

4. Molly had $21 to spend on two notebooks. After buying them he had $13. How much did each notebook cost?

Mathematics

2 answers:

otez555 [7]2 years ago

8 0

21-13=8
8/2=4
Each notebook costs $4
Hope this helps :)

blagie [28]2 years ago

3 0

First you do 21 - 13 and you get 8

8 divided by 2 notebooks = 4

Each notebook was $4.00

Hope this helps!

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Answer:

≈12.8

Step-by-step explanation:

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1 year ago

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Which equation results from taking the square root of both sides of (x + 9)2 = 25?

Alex_Xolod [135]

Answer:

√2.37+ 3 √9 = √5. 3 is the last one

x+9 =+25

Step-by-step explanation:

(x+9)2= 25 This means x= 3.5 and the square root of x = √3.5 = 1.87 square root of 9 x 2 = √18 =4.24

We can also see 18+7 =25

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3 years ago

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Musya8 [376]

Answer:

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Step-by-step explanation:

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3 years ago

You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first

Tomtit [17]

Answer:

$P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729$

And the probability of loss with the first wersion is 0.729

$P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774$

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=3, p=0.1)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

$P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729$

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

$Y \sim Binom(n=5, p=0.05)$

The probability mass function for the Binomial distribution is given as:

$P(Y)=(nCy)(p)^y (1-p)^{n-y}$

Where (nCx) means combinatory and it's given by this formula:

$nCy=\frac{n!}{(n-y)! y!}$

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

$P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774$

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

4 0

3 years ago

MZRSK = x + 53, m KST = x + 109,<br> and mZRST = 156º<br><br><br> Find x.

Dahasolnce [82]

Answer:

$-3 = x$

Step-by-step explanation:

Since we are not given a midpoint, we use the Angle Addition Postulate:

156 = [x + 109] + [x + 53]

156 = 162 + 2x

-162 - 162

_______________

−6 = 2x

___ ___

2 2

−3 = x

[−3 + 53] + [−3 + 109] = 156

50 106

156 = 156 ☑

Therefore, $-3 = x$ is a genuine statement.

I am joyous to assist you anytime.

4 0

3 years ago