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KIM [24]
3 years ago
15

My tens digit is double my ones digit. i am less then 70 and greater than 60.

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
4 0

The answer you are looking for would be 63.

63 is greater than 60, but less than 70, and the tens place (6) is double the ones place (3). Thus meaning 63 is the answer.

I hope this helps!

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maks197457 [2]

Answer:

dsg

Step-by-step explanation:

4 0
3 years ago
An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
2 years ago
91 is 130% of what number w?​
Nitella [24]

Answer:

70

Step-by-step explanation:

91 ÷ 1.3 = 70

5 0
3 years ago
Is the mix number of 17/3
Licemer1 [7]
This fraction \frac{17}{3}, is not a mixed fraction. 5 \frac{2}{3} is a mixed fraction.
6 0
2 years ago
Read 2 more answers
If the difference of a number and two is tripled, the result is six more than the number. Find the number. Round your answer to
Nataly [62]

Answer:

6

Step-by-step explanation:

let the number be x

(x-2)3=x+6

3x-6 = x+ 6

2x= 12

x= 6

8 0
2 years ago
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