Answer:
a=√x3y5 or a=−√x3y5
Step-by-step explanation:
Answer:
Lateral Area = Area of 2 triangle + Area of slant rectangle + area of back rectangle
Lateral Area = (5m)(3m) + (6m) (36m) + (3m) (36m)
LA = 15m² + 216m² + 108m²
LA = 339 m²
SA = (5m)(3m) + (6m) (36m) + (3m) (36m) + (5m)(36m)
SA = 15m² + 216m² + 108m² + 180 m²
SA = 519 m²
here's the solution,
- n = 11
- a = 5 ( a = first term )
- d = 6 ( d = common difference )
we know,
=》
=》
=》
=》
=》
nth term ( 11th term ) = 65
<u>Define x:</u>
Let the first number be x.
1st number = x
2nd number = x + 1
3rd number = x + 2
<u>Construct equation:</u>
x + x + 1 + x + 2 = 4(x + 1)
3x + 3 = 4(x + 1)
Answer: 3x + 3 = 4(x + 1)
The distance travelled is 10 m
The velocity gained at the end of the time is 2 m/s
<h3>Motion</h3>
From the question, we are to determine distance travelled and the velocity gained
From one of the equations of motion for <u>linear motion</u>, we have that
S = ut + 1/2at²
Where S is the distance
u is the initial velocity
t is the time taken
and a is the acceleration
First, we will calculate the acceleration
Using the formula,
F = ma
Where F is the force
m is the mass
and a is the acceleration
∴ a = F/m
Where F is the force
and a is the acceleration
From the given information,
F = 50 N
m = 250 kg
Putting the parameters into the equation,
a = 50/250
a = 0.2 m/s²
Thus,
From the information,
u = 0 m/s (Since the object was initially at rest)
t = 10 s
S = 0(t) + 1/2(0.2)(10)²
S = 10 m
Hence, the distance travelled is 10 m
For the velocity
Using the formula,
v = u + at
Where v is the velocity
v = 0 + 0.2×10
v = 2 m/s
Hence, the velocity gained at the end of the time is 2 m/s
Learn more on Motion here: brainly.com/question/10962624
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