1. 2x+3<-3 = x<-3
You get this by subtracting 3 from both sides, which gives you -6. Then divide 2 from both sides.
2. -3x<-6 = x>2
You divide -3 from both sides. You must switch the sign because any time you multiply or divide a negative integer from both sides of an inequality the sign is switched.
3. -5x<5 = x>1
See number 2
4. 5-2x<11 = x>-3
Subtract 5 from both sides to get -2x<6. Then, divide both sides by -2 and switch the sign.
5. x+2<5 = x<3
Subtract 2 from both sides
6. 2-3x<5 = x>-1
Subtract 2 from both sides to get -3x<3. Then, divide -3 from both sides and switch the sign.
X= 45
so 2x -> 2(45) would be 90
Answer:
<em>8 14/45</em>
Step-by-step explanation:
First, place 8/9 anywhere there is a y:
6+8(8/9-3/5)
Next, do what is in the parenthesis. Make both fractions have the same denominator.
6+8(40/45-27/45)
And now subtract:
6+8(13/45)
Now, multiply 8 and 13/45:
6+ 104/45
Convert the fraction to a mixed fraction:
2 14/45
Finally, add 6:
8 14/45
<h3>
Hopefully I helped :)</h3>
Answer:
Both type of numbers have a decimal point but the decimal numbers can contain digits other than 0 so you have to worry for these numbers when you're multiplying and the placement of the decimal point in the answer.
A way think about it is sum the total numbers after the decimal point, this work because the numbers can be represented as fractions (explanation below) so If one factor has 2 decimal places and another factor has 1 decimal place the answer have 3 decimal places.
Step-by-step explanation:
A whole can be represented as 2 and so on, while a decimal number is represented as 3.14 when the numbers after the decimal point can be different of 0.
So when you multiply two decimal numbers check the total number of number after the decimal point and sum these amounts.
Where the total number of numbers after the decimal point is equal to the power of 10 in the denominator that's mean equal to 3. However this method takes more time, so is more simply to say that the total of numbers after the decimal point is the sum of the total of numbers after the decimal point of each decimal number.
Add e to both sides and subtract 2 from both sides :: v+f-2=e
