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ser-zykov [4K]
3 years ago
6

" Pentagon ABCDE and pentagon A’B’C’D’E’ are shown on the coordinate plane below.

Mathematics
2 answers:
Zielflug [23.3K]3 years ago
5 0

Pentagon ABCDE has vertices with coordinates A(-5,-2), B(-7,-3), C(-6,-6), D(-3,-5) and E(-3,-3).

1. Apply the translation (x, y) → (x + 2, y + 8) to the pentagon ABCDE. Then the coordinates of vertices of image pantagon A''B''C''D''E'' will be:

  • A(-5,-2)→A''(-3,6),
  • B(-7,-3)→B''(-5,5),
  • C(-6,-6)→C''(-4,2),
  • D(-3,-5)→D''(-1,3),
  • E(-3,-3)→E''(-1,5).

2. Apply to the pentagon A''B''C''D''E'' the reflection across the y-axis that has a rule (x,y)→(-x,y). Then the coordinates of image pentagon A'B'C'D'E' will be:

  • A''(-3,6)→A'(3,6),
  • B''(-5,5)→B'(5,5),
  • C''(-4,2)→C'(4,2),
  • D''(-1,3)→D'(1,3),
  • E''(-1,5)→E'(1,5).

As you can see from the diagram these obtained coordinates are exactly the same as the coordinates  of drawn points.

Answer: correct choice is C.

Tema [17]3 years ago
4 0
C. translated according to the rule (x,y) > (x+2,y+8) and reflected across the y-axis
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Probability that card is queen given card is club P(A\cap B)=\frac{4}{52}=\frac{1}{13}

Probability that card is club from deck of 52 cards P(B)=\frac{13}{52}=\frac{1}{4}

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