Answer:
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Step-by-step explanation:
In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.
Given function is:

Taking first derivative

Now the first derivative has to be put equal to zero to find the critical value

The function has only one critical value which is 5.
Taking 2nd derivative


As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5
The value can be found out by putting x=5 in the function

Hence,
<u>The function y = x 2 - 10x + 31 has a minimum value of 6</u>
Hence,
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Answer:
3n+12=45
Step-by-step explanation:
Because if you take 2 and put it in the place of n 32+12 =45 and take 45 and divide it by 12 and you will get 11.
16 x 3/8 so 16/1 x 3/8 = 48/8. 48 divided by 8 is 6. So 6 inches.
Sub in the values and solve for W
50=3W+14
50-14=3W
36=3W
12=W
The team won 12 games.
12+14=26 (games drawn and won)
35-26=9
Therefore they lost 9 games
The ratio of the distance between the foci and the length of the <em>major</em> axis is called eccentricity.
<h3>
Definitions of dimensions in ellipses</h3>
Dimensionally speaking, an ellipse is characterized by three variables:
- Length of the <em>major</em> semiaxis (
). - Length of the <em>minor</em> semiaxis (
). - Distance between the foci and the center of the ellipse (
).
And there is the following relationship:
(1)
Another variable that measure how "similar" is an ellipse to a circle is the eccentricity (
), which is defined by the following formula:
,
(2)
The greater the eccentricity, the more similar the ellipse to a circle.
Therefore, the ratio of the distance between the foci and the length of the <em>major</em> axis is called eccentricity. 
To learn more on ellipses, we kindly invite to check this verified question: brainly.com/question/19507943