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Romashka-Z-Leto [24]
3 years ago
13

Rotate the cracker either 90 degrees or 180 degrees and either CW or CCW around each of the three points A, B, C. When does the

cracker end up in the same new position
Mathematics
1 answer:
almond37 [142]3 years ago
3 0
I need a picture so that I could see the diagram
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The ratio of corresponding sides of the first triangle to the second triangle below is
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Answer:

no

Step-by-step explanation:

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Solve by using substitution<br> x=3y−2<br><br> 2x-5y=-22x−5y=−2
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Uyuu WUR MIUToques<br> 1 x + 2x - 7 = 0
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235 x 80<br> (200x ___)+ (30 x____)+(5x___)<br> _____ +_____+_____<br> _____
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3 years ago
A student placement center has requests from five students for interviews regarding employment with a particular consulting firm
bagirrra123 [75]

Answer: a) 1 / 10

b) 3 / 10

c) 1 / 5

d) 3 / 5

Step-by-step explanation:

Total number of requests five students for interviews regarding employment with the consulting firm = 5

Number of students that are maths majors = 3

Probability of selecting a maths student is 3 / 5

Number of students that are statistics majors = 2

Probability of selecting a statistics student is 2 / 5

a) the probability that both selected students are statistics majors

= 2 / 5 × 1 / 4 = 2 / 20 = 1 / 10

b) the probability that both students are math majors

= 3 / 5 × 2 / 4 = 6 / 20 = 3 / 10

c) the probability that at least one of the students selected is a statistics major will be p( one statistics and the other, maths) + p( one maths and the other, statistic) - p( both are mathematics)

= (2 / 5 × 1 / 4 ) + ( 2 / 5 × 3 / 4 ) - (3 / 5 × 2 / 4)

= 2 / 10 + 6 / 20 - 6 / 20

= 1 / 5 + 3 / 10 - 3 / 10

= 1 / 5

d) the probability that the selected students have different majors is p(one is maths and the other is statistics) + p(one is statistics and the other is maths)

(3 / 5 × 2 / 4) + (2 /5 × 3 / 4)

= 6 / 20 + 6 / 20 = 12 / 20

= 3 / 5

3 0
3 years ago
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