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Mariana [72]
3 years ago
11

Find the annual interest rate Twenty is 20% more than what number?

Mathematics
1 answer:
True [87]3 years ago
8 0

100/6

120/100 x = 20

x = 100/6 = 50/3

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Find the mean and median of the data. <br><br> 4.7,8.51,6.5,7.42,9.64,7.2,9.3
Murrr4er [49]

Answer:

Population size: 7

Median: 7.42

Minimum: 4.7

Maximum: 9.64

First quartile: 6.5

Third quartile: 9.3

Interquartile Range: 2.8

Outliers: none

5 0
3 years ago
what is the following product of assume Y is greater than or equal to 0 square root y to the third Times Square Root why 2/3​
sattari [20]

Step-by-step explanation:

\sqrt{y3}  \times   \sqrt{y3}

\sqrt{y3 \times y3}

\sqrt{y3 + 3}

\sqrt{y6}

4 0
2 years ago
Katie draws two chords in a circle in a certain way. She then draws in four segments between adjacent endpoints of the chords to
FromTheMoon [43]
Answer: The answer that is not true is choice D.

If Katie drew those chords and those line segments to form a square, then the diagonals would have to be congruent. The only way to have them would be through the center, therefore they must be diameters.

And if it is a square, then the diagonals are perpendicular bisectors meaning the angles would be right angles not acute or obtuse as in Choice D. <span />
7 0
3 years ago
What property is 5x1/5=1
alisha [4.7K]

Answer:

Multiplicative Identity Property

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
3. (05.06 MC)
AveGali [126]

Answer:

Step-by-step explanation:

y > 3x + 10

y < -3x - 1

<h3> Part A:</h3>

You'd graph the given systems of linear inequalities the same way as you graph the linear equations.  

To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph.  Use a dashed line (because of the ">" symbol).  

Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).  

Pick a test point on either side of the boundary line and plug it into the original problem.  This will help determine which side of the boundary line is the solution.  Plug in a test point that is not on the boundary line.

Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.  

y > 3x + 10

0 > 3(0) + 10

0 > 0 + 10

0 > 10 (False statement).  

y < -3x - 1

0 < -3(0) - 1

0 < 0 - 1

0 < -1 (false statement).  

Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.  

<h3>Part B: </h3>

You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.  

y > 3x + 10

10 > 3(8) + 10

10 > 24 + 10

10 > 34 (False statement).  

y < -3x - 1  

10 < -3(8) - 1

10 < -24 - 1

10 < -25 (false statement).  

Therefore, (8, 10) is not a solution to the system.    

8 0
3 years ago
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