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prohojiy [21]
3 years ago
11

Factor the following expression using the GCF: 42pr – 3p. Please help!

Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

3p(14r-1)

Step-by-step explanation:

Factor out by 3 since 42 and 3 are both divisible by 3: 3(14pr-p)

Since "p" can be factored out, we then have: 3p(14r-1)

So what we found out was that the GCF of 42pr-3p is 3p

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Option B:

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

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where I_0=1\times10^{-12}\ \text {watts}/ \text m^2}

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

10^{12}

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$10^{12}=\left(\frac{I}{I_0} \right)

$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)

Now, do the cross multiplication,

I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{0} \ \text {watts}/ \text m^2}

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Option B is the correct answer.

Hence I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}.

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3 years ago
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Answer:

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