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EastWind [94]
2 years ago
14

Find the least common denominator for these

Mathematics
1 answer:
baherus [9]2 years ago
8 0

Answer:

The least common denominator of the two rational expressions is (x+2)^{2}\cdot (x+3).

Step-by-step explanation:

Let be the following rational expressions:

\frac{x^{3}}{x^{2}+4\cdot x + 4}, \frac{-9}{x^{2}+5\cdot x + 6}

Then, we factor each denominator:

\frac{x^{3}}{(x+2)^{2}}, \frac{-9}{(x+3)\cdot (x+2)}

Now, we compare each denominator to find all missing binomials so that each expression may have a common denominator:

\frac{x^{3}}{(x+2)^{2}} \rightarrow (x+3)

\frac{-9}{(x+3)\cdot (x+2)} \rightarrow (x+2)

Hence, we conclude that least common denominator of the two rational expressions is (x+2)^{2}\cdot (x+3).

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Cup G has a diameter of 4 in. and a height of 8 in. Find the volume of Cup G.
horsena [70]

Answer:

32pi

Radius=1/2 Diameter

radius=2

Area of circle= pi*radius^2= 4pi

4pi*8=32 pi

5 0
3 years ago
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PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS
Elina [12.6K]

You want to end up with A\sin(\omega t+\phi). Expand this using the angle sum identity for sine:

A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi

We want this to line up with 2\sin(4\pi t)+5\cos(4\pi t). Right away, we know \omega=4\pi.

We also need to have

\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}

Recall that \sin^2x+\cos^2x=1 for all x; this means

(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}

Then

\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)

So we end up with

2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)

8 0
3 years ago
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Square T was translated by the rule (x + 2, y + 2) and then dilated from the origin by a scale factor of 3 to create square T″.
Delicious77 [7]

Answer: OPTION C.

Step-by-step explanation:

It is important to know the following:

<u> Dilation:</u>

  • Transformation in which the image has the same shape as the pre-image, but the size changes.
  • Dilation preserves betweenness of points.
  •  Angle measures do not change.

<u>Translation:</u>

  • Transformation in which the image is the same size and shape as the pre-image.
  • Translation preserves betweenness of points.
  • Angle measures do not change.

Therefore, since the Square T was translated and then dilated to create Square T'', we can conclude that the statement that explains why  they are similar is:

<em>Translations and dilations preserve betweenness of points; therefore, the corresponding sides of squares T and T″ are proportional.</em>

6 0
3 years ago
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Pls help i will give you 30 points asap
Olegator [25]

In y = mx + b form, the slope can be found in the m position and the y intercept can be found in the b position.

y = mx + b

y = 2x + 15

slope(m) = 2 and y int (b) = 15

The initial amount is the y intercept, which is 15. The rate of change (the slope) is 2

example :  

baskets picked in 1 hr :

y = 2(1) + 15

y = 2 + 15

y = 17

baskets  picked in 2 hrs :

y = 2(2) + 15

y = 4 + 15

y = 19

so the slope ( rate of change) is basically saying for every hr of picking, you pick 2 baskets...so your picking 2 baskets per hr.

The y intercept (15) is telling us that they already had 15 baskets to start with.

3 0
3 years ago
HELP PLEASE,
faltersainse [42]
I think it's D but make it sire
7 0
3 years ago
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