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EastWind [94]
3 years ago
14

Find the least common denominator for these

Mathematics
1 answer:
baherus [9]3 years ago
8 0

Answer:

The least common denominator of the two rational expressions is (x+2)^{2}\cdot (x+3).

Step-by-step explanation:

Let be the following rational expressions:

\frac{x^{3}}{x^{2}+4\cdot x + 4}, \frac{-9}{x^{2}+5\cdot x + 6}

Then, we factor each denominator:

\frac{x^{3}}{(x+2)^{2}}, \frac{-9}{(x+3)\cdot (x+2)}

Now, we compare each denominator to find all missing binomials so that each expression may have a common denominator:

\frac{x^{3}}{(x+2)^{2}} \rightarrow (x+3)

\frac{-9}{(x+3)\cdot (x+2)} \rightarrow (x+2)

Hence, we conclude that least common denominator of the two rational expressions is (x+2)^{2}\cdot (x+3).

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How do I do this? Please provide steps.
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Answer:

3/5

Step-by-step explanation:

Soh Cah Toa

In some trigonometry classes, this acronym is very important to solving questions like this.

Why?

It tells us the right triangle-definition of these trigonometry functions.

We have that cosine of an angle is equal to tge side that is adjacent to it over the hypotenuse.

So here we are asked to find cos(B).

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6 0
3 years ago
The coordinates of the vertices of A DEF are D(-4,1), E(3. – 1), and F(-1, – 4)
liq [111]

Answer:

ΔDEF is not a right triangle because no two sides are perpendicular.

Step-by-step explanation:

The coordinates of the vertices of ΔDEF are given to be D(-4,1), E(3,-1) and F(-1,-4).

Now length of DE is given by \sqrt{(-4-3)^{2}+(1-(-1))^{2}  } =\sqrt{53} units

length of EF is given by \sqrt{(3-(-1))^{2}+(-1-(-4))^{2}  }=\sqrt{25} units

and length of FD is given by \sqrt{(-4-(-1))^{2}+(1-(-4))^{2}  } =\sqrt{34} units.

Therefore, 53 ≠ 25+34

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So, ΔDEF is not a right triangle because no two sides are perpendicular. (Answer)

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3 years ago
there are 3 times as many adults as children at a book fair what is the ratio of people at the book fair​
kakasveta [241]

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1:3

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3 years ago
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