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aivan3 [116]
3 years ago
11

Simplify 7(x + 3). how could i find the answer to this question?

Mathematics
2 answers:
padilas [110]3 years ago
5 0

7(x + 3) = 7x + 21

------------------------


julia-pushkina [17]3 years ago
5 0
You multiply the 7 by both the x and 3
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Landon buys some of his clothes second hand. If 40% of his shirts are second hand and he owns 65 shirts, how many of Landon's sh
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Answer:

26

Step-by-step explanation:

6.5 is 10% of 65, so to find 40% of 65 we multiply 6.5*4=26

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What is the area of the following figure?
Snowcat [4.5K]

Answer:

16.56‬

Step-by-step explanation:

The area of the square is 2 × 2

The area of the circle is-

A=πr²

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AnnyKZ [126]

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8 0
3 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
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