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love history [14]
3 years ago
8

Find surface area of a rectangle

Mathematics
1 answer:
fgiga [73]3 years ago
6 0
In order to find the surface area of a rectangle:

-- Find or measure the length of the rectangle.

-- Find or measure the width of the rectangle.

-- Make sure both quantities are in the same units. 
If they're not, then convert one or the other so that they are.

-- Multiply the two numbers.

The product is the area of the rectangle, in units of
square-(the unit in which the dimensions are measured).
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rusak2 [61]

Answer:

Step-by-step explanation:
The rules For fractions: Multiple Denominator to Denominator and Numerator to numerator!

Ok: For number 1

3/5*1/1= 3/5

Number 2

3/4*9/4=27/16= 1 11/16

Number 3

14/21=2/3*33/7=66/21= 3 3/21= 3 1/7

Number 4

6/18*9/42= 1/3*3/14= 3/42= 1/14

Number 5

22/15*45/4= 33/2=16 1/2

Number 6

3/28* 35/6= 105/168= 5/8

Number 7

2/7*35/12=60/84=5/6

Number 8

16/15*21/24=16/15* 7/8=112/120=14/15

Hope It helps!!!!

7 0
1 year ago
Please help me asap <br> What is the value of x? 3 6 27 72
fredd [130]
The answer to your question is 3
5 0
3 years ago
Let v1=(1, 6) and v2=(5, -3)
astraxan [27]

Answer:

See Explanation;

Step-by-step explanation:

The given vectors are;

v_1=\:\: and v_2=\:\:

a) To add or subtract two vectors, we add or subtract their corresponding components

v_1+v_2=\:\:+\:\:

v_1+v_2=\:\:

v_1+v_2=\:\:

v_1-v_2=\:\:-\:\:

v_1-v_2=\:\:

v_1-v_2=\:\:

v_2-v_1=\:\:-\:\:

v_2-v_1=\:\:

v_2-v_1=\:\:

b) See attachment for graphs(1,6

3 0
3 years ago
Someone please help me
Paha777 [63]
If im correct it is 38yd cubed 

3 0
3 years ago
Read 2 more answers
Write the slope-intercept form of the equation of each line.
gregori [183]

Greetings!

Answer:

2y = x - 6

Step-by-step explanation:

First, we must find the slope of the current equation.

This is the number in front of the x.

Seeing as this is -2x, the slope of this line is -2

When finding the slope of a line perpendicular, you need to find the \frac{-1}{slope}

So, in this case it is:

\frac{-1}{-2}

The negatives cancel out which leave \frac{1}{2}

So the gradient is \frac{1}{2}


Now, to find the equation of a line, you need to use:

y - y1 = m(x - x1)

Where ya and x1 are the values in the coordinates (2 , -2)

So y1  = -2, x1 = 2, and m is a half. Plug these values in:

y - - 2 = \frac{1}{2}(x - 2)

We need to get rid of the half so we multiply the whole equation by 2:

2y - - 4 = (x - 2)

The minus and the negative turn into a positive:

2y + 4 = x - 2

And now simply move the +4 over to the other side, making it a negative:

2y =  -2 - 4 + x

Simplify:

2y = x - 6

<h3>So the equation of the line is 2y = x - 6</h3>
<h2>Hope this helps!</h2>
5 0
3 years ago
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