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KonstantinChe [14]
3 years ago
8

I need help with this topic

Mathematics
1 answer:
madreJ [45]3 years ago
4 0
Let's go through these, sentence by sentence:

a. <em>Henry is driving at a constant speed.</em>

If the y-axis represents the speed of Henry's car, this portion of the graph should be a straight horizontal line, as his speed doesn't change at all. This already eliminates the first and second options.

<em>He then slows down to pass an accident. After passing it, he goes back to his original speed and continues driving at that speed</em>.

We should see a downward-sloped line segment during the period when he slows down, and then an upward-sloped line segment during the time where he speeds up. Graphically, this would look like a V. Finally, the graph would again become a straight horizontal line as he returned to and maintained his original speed. Graph #4 is the only one which represents this description.

b. <em>Teresa is driving to work. She drives at a constant speed for several miles, then stops to pick up breakfast</em>.

On all of the graphs of this situation, the y-axis represents Teresa's <em>distance to work</em>. We have to be careful here, because the further she drives, <em>the further down the graph goes</em>. The y-coordinate starts at some positive fixed position (the total distance to work) and works its way down to 0.

There's only one graph which represents this scenario - a downwards trend - and that's graph #3.
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All the edges of a regular square pyramid have length 8. find the Volume of the pyramid, Lateral area of the pyramid and the Tot
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V = 120.6796

LA = 110.8513

SA = 174.8513

Step-by-step explanation:

Let me know if you need more of an explanation for any of these

First we need the height, one way to find that out is to use the diagonal of the  and one of the diagonal edges of the pyramid.  Specifically we will need half of the diagonal of the square.  We will call the diagonal of the square d.

8^2+8^2=d^2\\d=\sqrt{64+64} \\d=\sqrt{128}

Gonna leave it like that for ease of writing.  So then half of the diagonal is \frac{\sqrt{128}}{2}

The height, h, will be (\frac{d}{2})^2+h^2 = 8^2.  Plugging everything in gets us h=\sqrt{32}

last, we need to find slant height, which we will call s.

(\frac{8}{2})^2+h^2 = s^2\\s=\sqrt{48}

s is also the height of the triangles for purposes of finding area.  Now for the volume and areas.

Volume is area of the base times height divided by 3, so V=8^2\frac{\sqrt{32} }{3}  = \frac{64\sqrt{48} }{3} = 120.6796

Lateral area is the sum of the four areas of the triangles, and each of those are \frac{8*h}{2} so the whole lateral area is 4 times that.  So we get 4\frac{8\sqrt{32} }{2} =110.8513

Total surface area is the lateral surface area + the area of the base, so 110.8513 + 64 = 174.8513

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Will mark Brianliest answer correctly !!!!!!!!!! Pleaseeee helpppp !!!!!!!!!!!!!!!!!
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It would be 2 Square root 10

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