Answer:
x = theta = 0°
Step-by-step explanation:
Given the trigonometry function
Tan²x/2-2 cos x = 1
Tan²x-4cosx = 2 ... 1
From trigonometry identity
Sec²x = tan²x+1
tan²x = sec²x-1 ... 2
Substituting 2 into 1, we have:
sec²x-1 -4cosx = 2
Note that secx = 1/cosx
1/cos²x - 1 - 4cosx = 2
Let cosx. = P
1/P² - 1 - 4P = 2
1-P²-4P³ = 2P²
4P³+2P²+P²-1 = 0
4P³+3P² = 1
P²(4P+3) = 1
P² = 1 and 4P+3 = 1
P = ±1 and P = -3/4
Since cosx = P
If P = 1
Cosx = 1
x = arccos1
x = 0°
If x = -1
cosx = -1
x = arccos(-1)
x = 180°
Since our angle must be between 0 and 1 therefore x = 0°
Answer:
The answer is 1/6y+1/6(y+12)-2
Step-by-step explanation:
I used a math calculator.
1) x² + y² = 64 is the EQUAION of a cercle with a radius R = √64 =8
2) The cross section is a triangle with H = BASE.
Since R = 8 that means the Base B= 16 and also the height H =16
This solid is then a regular cone and its Volume value is
V = πR².H
V π(8)².(16) = 2014π units³ or ≈ 3217 units³
