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3 years ago

Box method division with remainders

Mathematics

1 answer:

rosijanka [135]3 years ago

3 0

Answer:

U have dummy

Step-by-step explanation:

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Can some please explain and solve how to do these unit rate equations?

Sedaia [141]

(1) 20:4=5:1. 80:16 16 weeks since he’s doing 5per week, and 80 divided by 5 is 16.

(2) 6:3=2:1. 10:5 It will take 5 hours because she’s walking 2km per hour, so it would take 5 hours to walk 10km.

(3) 1:20 4:80 It will take 80 minutes because 20x4=80

(4) 1:1 20:20 it will take her 20 days since she makes one craft a day and she’s making 20.

(5) 12:1 84:7 84 cakes since there is 7 days in a week. 12x7=84

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8 0

2 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

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2 years ago

The set of ordered pairs in the mapping below can be described as which of the following?

PIT_PIT [208]

Because the x numbers are used more than once it cannot be a function. As for the the relation if its going through the origin then it would be a relation. im going to go with D

4 0

3 years ago

Rearrange x = 7y - 5 to make y the subject.

nalin [4]

By rearranging x = 7y - 5 to make y the subject, we get

x + 5 = 7y ( By transposition method )

or, $\huge \purple {\tt {\frac{x + 5}{7} = y}}$