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LuckyWell [14K]
3 years ago
7

Box method division with remainders

Mathematics
1 answer:
rosijanka [135]3 years ago
3 0

Answer:

U have dummy

Step-by-step explanation:

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The sum of two numbers is 51. The larger number is 17 more than the smaller number. What are the numbers ?
Serggg [28]

Answer:

The numbers are 17 and 34.

Step-by-step explanation:

I just subtracted 17 from 51, it equals 34, and 34 is 17 more than 17. Add 34 and 17 and you get 51.

4 0
3 years ago
The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w
dimulka [17.4K]

Answer:

99% CI:

-4.637\leq\mu_v-\mu_o\leq 3.737

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

s_{Md}=\sqrt{\frac{2MSE}{n_h}}

The MSE can be calculated as

MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65

The weighted sample size nh can be calculated as

n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16

The standard deviation then becomes

s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

\Delta M=M_v-M_o=5.10-5.55=-0.45

Then the confidence interval can be constructed as

\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737

8 0
3 years ago
Below is a family of facts . Select the boxes to show the complete family of facts.
vladimir2022 [97]
Dfynnkkibbfddcceatkkmjygvv
5 0
3 years ago
Solve the quation by completing the square . round to the nearest hundredth if nessarsy x2-x-7=0
Anestetic [448]

Answer:

3.19

Step-by-step explanation:

6 0
3 years ago
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is .....a.2 b.-2 c 1/2 d.none ​
blsea [12.9K]

Answer:

k=2

Problem:

if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..

Step-by-step explanation:

Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.

So we want the following:

[(k+2)/2]^2=2k

Apply the power on the left:

(k+2)^2/4=2k

Multiply both sides by 4:

(k+2)^2=8k

Expand left side:

k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2

Subtract 8k on both sides:

k^2-4k+4=0

Factor using the identity mentioned a couple lines above:

(k-2)^2=0

Since zero squared is zero, we want k-2=0.

Adding both sides by 2 gives k=2.

8 0
3 years ago
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