1.<span>
The midpoint </span>MPQ of PQ is given by (a + c /
2, b + d / 2)<span>
2.
Let the x coordinates of the vertices of P_1 be :
x1, x2, x3,…x33
the x coordinates of P_2 be :
</span>z1, x2, x3,…z33<span>
and the x coordinates of P_3 be:
w1, w2, w3,…w33</span>
<span>
3.
We are given with:
</span>
X1
+ x2 + x3… + x33 = 99
We also want to find the value of w1 + w2 + w3… + w33.<span>
4.
Now, based from the midpoint formula:</span>
Z1 = (x1 + x2) / 2
Z2 = (x2 + x3) / 2
Z3 = (x3 + x4) / 2
Z33 = (x33 + x1) / 2<span>
and
</span>
<span>W1
= (z1 + z1) / 2
W2 = (z2 + z3) / 2</span>
<span>W3
= (z3 + z4) / 2
W13 = (z33 + z1) / 2
.
.
5.</span>
<span>W1
+ w1 + w3… + w33 = (z1 + z1) / 2 + (z2 +
z3) / 2 + (z33 + z1) / 2 = 2 (z1 + z2 + z3… + z33) / 2</span>
<span>Z1
+ z1 + z3… + z33 = (x1 + x2) / 2 + (x2 + x3) / 2
+ (x33 + x1) / 2
</span>2 (x1 + x2 + x3… + x33) / 2 = (x1 + x2 +
x3… + x33 = 99<span>
<span>Answer: 99</span></span>
<u>Answer:
</u>
The fraction of the bleachers filled with the home team is 
<u>Solution:
</u>
Given that,
The bleachers at the football game are 
In those bleachers 
of the fans are rooting for the home team
So, the fans that are filled with the home team is \left(\left(\frac{7}{8}\right) \times\left(\frac{1}{2}\right)\right)
Hence, the required fraction is \left(\left(\frac{7}{8}\right) \times\left(\frac{1}{2}\right)\right)
Removing the brackets we get,
\frac{7 \times 1}{8 \times 2}
=
The required fraction is
10,because 20 times 10 = 200
Answer:1.21x
Step-by-step explanation:
Let the initial population was x
(1.1x)*1.1=1.21x
Answer:
Step-by-step explanation:
