A substance has a mass of 10g and a volume of 5cm^3 whats the density
1 answer:
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Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190
has a pvalue of 0.8944
X = 185
has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Answer:
The answer is "152 ft"
Step-by-step explanation:
Please find the attached file.
The area of the square can be found on the foot.
The area of the triangular front will then be calculated
Since each has two sides, .
Therefore the multiplying the area of the bottom square by the number of cells to get 152.
