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3 years ago

Find the doubling time of an investment earning 7% interest if interest is compounded continuously

Mathematics

1 answer:

Alex3 years ago

5 0

Answer:

The doubling time of this investment would be 9.9 years.

Step-by-step explanation:

The appropriate equation for this compound interest is

A = Pe^(rt), where P is the principal, r is the interest rate as a decimal fraction, and t is the elapsed time in years.

If P doubles, then A = 2P

Thus, 2P = Pe^(0.07t)

Dividing both sides by P results in 2 = e^(0.07t)

Take the natural log of both sides: ln 2 = 0.07t.

Then t = elapsed time = ln 2

--------- = 0.69315/0.07 = 9.9

0.07

The doubling time of this investment would be 9.9 years.

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1+√3+1-√3 1 * 604 * 909

brilliants [131]

1 + √3 + 1 - √3

= 1 + 1

= 0

1 * 604 * 909

= 549,036

6 0

3 years ago

Read 2 more answers

A car starts from an initial velocity of 10m/s and accelerates at 2.5m/s².how long will it take the car to reach a speed of 40m/

PIT_PIT [208]

A=(v-u)/t
We know a=2.5, v=40, u=10, so:
2.5=(40-10)/t
2.5t=40-10
2.5t=30
Divide both sides by 2.5
t=12 It takes 12 seconds for the car to reach 40m/s

To find out how far it went, you do:
d=v+1/2 at^2
d=10+1/2(2.5)(12)^2
d=10+1/2(2.5)(144)
d=10+(1.25)(72)
d=10+90
d=100m

Hope this helps :)

7 0

3 years ago

Find the equation of the line through (-9,6) that is perpendicular to the line through (7,8),

Setler [38]

Step-by-step explanation:

I assume as "equation" we mean the slope-intercept form :

y = ax + b

"a" is the slope of the line (y coordinate change / x coordinate change when going from one point to another on the line). b is the y-intercept (the y value when x = 0).

we get the slope by finding the perpendicular slope of the first line.

the slope of the first line when going from (-3, -9) to (7, 8) :

x changes by + 10 (from -3 to +7).

y changes by + 17 (from -9 to +8).

so, that slope is 17/10.

the perpendicular slope is turning the original slope upside-down and flips the sign :

-10/17

so, a = -10/17

now, as we have only the slope and a point of the new line, we can use the point-slope form to stay and then transfer into the slope-intercept form.

y - y1 = a(x - x1)

where "a" is again the slope, and (x1, y1) is a point on the line

y - -6 = -10/17 × (x - -9)

y + 6 = -10/17 × (x + 9) = -10/17 × x - 90/17

y = -10/17 × x - 90/17 - 6 =

= -10/17 × x - 90/17 - 102/17 =

= -10/17 × x - 192/17

so, the equation is (in a maybe nicer way)

y = -1/17 × (10x + 192)

7 0

1 year ago

Imma keep on saying this I understand some of it but not all againnnn I’m sorryyy

Mariulka [41]

Answer:

6) The answer is 210p - 105

7) The answer is -124q + 216

Step-by-step explanation:

1. Always Distributive Property first

6) -14 (8 - 15p) 7) -12 ( -18 + 10q)

-112 +210p 216 -120q

2. Combine like terms

6) -112 + 7 = -105 your full answer is 210p -105

7) -120q + -4q = -124q Your full answer is -124q +216.

Hope this helps.

6 0

3 years ago

Write the equation of a line that passes through the points (-2, 3) and (-4, 4) in slope intercept form (y=mx+b).

Yuri [45]

Step-by-step explanation:

first step is to find the gradient of the line which "m" on the equation

gradient formula is y2 - y1 ÷ x2 - x1 = -½ as shown on the picture we substituted those points given

2nd step is to substitute on the equation y=mx+c

m= -½

y= 3 (you can choose any from those given points but in my case I chose point A)

x= -2

c= ? only unknown variable so we can can calculate it

substitute as shown on the picture to get c= 2

therefore our equation of the line will be y= -½x+2

4 0

3 years ago