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Reptile [31]
3 years ago
5

Does the data in the table represent a direct variation or an inverse variation? Write an equation to model the data in the tabl

e.
(x) 1 l 2 l 5 l 10
(y) 40 l 20 l 8 l 4
A: Direct Variation; y= 40x
B: Inverse Variation; y= 1/40x
C: Direct Variation; xy= 40
D: Inverse Variation; xy= 1/40

Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0
We know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx
and 
A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form y*x=k or y=k/x

the answer is<span>
represent an inverse variation
k=40
</span>

<span>x*y=40

</span>see the attached figure

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\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind.

\bf f(x)=\sqrt[3]{x}\qquad \boxed{-f(x+2)+4}\implies f(x)=\stackrel{A}{-1}\sqrt[3]{\stackrel{B}{1}x\stackrel{C}{+2}}\stackrel{D}{+4}\qquad &#10;\\\\\\&#10;f(x)=-\sqrt[3]{x+2}+4

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check the picture below.

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3 years ago
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