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3 years ago

What is a 90 degree counter clockwise rotattion on a graph

1 answer:

7 0

<h2><u>Answer:</u></h2><h2>90 Degree Rotation</h2><h2>When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative.</h2>

<h2><u>Thank you</u></h2><h2><u>sunshinemadison101</u></h2>

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The smaller triangle is the image of the larger triangle after a dilation. The center of the dilation is (4,2). What is the scal

zzz [600]

Small triangle: <span>The side // x axis has a length of 4
Large triangle: The side // x axis has a length of 12

So Small/Large = 4/12 = 1/3

Small triangle: <span>The side // y axis has a length of 3
Large triangle: The side // y axis has a length of 9

</span><span>So Small/Large = 3/9 = 1/3

So the scale factor to obtain this dilatation is 1/3</span>

</span>

7 0

3 years ago

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Which sentence explian why the slope of AB is equal to the slope BC ?

slava [35]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Are this two triangles similar?

Alex73 [517]

<h3>Answer: </h3><h3>Yes, the triangles are similar</h3><h3>AC = 6</h3>

======================================================

Explanation:

Focus on triangle ABC. Let's find the missing angle

A+B+C = 180

113+B+22 = 180

B+135 = 180

B = 180-135

B = 45

Between the triangles, have two pairs of angles that are congruent

A = D = 113

B = E = 45

Which is enough to prove the triangles are similar through the angle angle (AA) similarity theorem. This must mean that C = F = 22

Since we have A pair with D, and B pair with E, this means that $\triangle ABC \sim \triangle DE F$

The order of the letters is important so we know how the angles pair up. The first letters pair up together, the second letters pair up, and so on.

Consequently, this means sides BC and EF pair up and AC and DF pair up

We can then say...

BC/EF = AC/DF

18/12 = x/4

18*4 = 12*x

72 = 12x

12x = 72

x = 72/12

x = 6

AC = 6

5 0

3 years ago

The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista

baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{10.634 - \mu}{\sigma}$

$10.634 - \mu = 1.28\sigma$

$\mu = 10.634 - 1.28\sigma$

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{9.7565 - \mu}{\sigma}$

$9.7565 - \mu = -1.96\sigma$

$\mu = 9.7565 + 1.96\sigma$

We also have that:

$\mu = 10.634 - 1.28\sigma$

$10.634 - 1.28\sigma = 9.7565 + 1.96\sigma$

$1.96\sigma + 1.28\sigma = 10.645 - 9.7565$

$3.24\sigma = 0.8885$

$\sigma = \frac{0.8885}{3.24}$

$\sigma = 0.2742$

The mean is

$\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65$

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0

4 years ago

Use the permutation formula to solve a problem when n = 15 and r = 4.

barxatty [35]

$nPr = \frac{n!}{(n - r)!}$

$15P4 = \frac{15!}{(15 - 4)!} = \frac{15!}{11!} \\ = \frac{15 \times 14 \times 13 \times 12 \times 11!}{11!} \\ 15 \times 14 \times 13 \times 12 = 32760$

3 0

3 years ago

Read 2 more answers