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ycow [4]
3 years ago
14

If y=5x-3 and 3x-y=-1, what is the value of y

Mathematics
2 answers:
Elan Coil [88]3 years ago
8 0
1 is the answer! Hope this helps
Svet_ta [14]3 years ago
3 0
Well if you make them both equal to y I got...
Y=-3x+1
Y=5x-3
But I don't think you can find it without the y since they are different variables. Like I know -3x and 5x are the slopes and 1 and -3 are the y intercepts but I'm stuck after that. Sorry if that wasn't any help.
Hope I helped.
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Justin is asked to solve the following system of linear equations using the elimination method.
romanna [79]

Alright, lets get started.

Justin is asked to solve the linear equations using elimination method.

By using elimination method means we have to multiply some numbers in our given equations in such a way that the co-efficient of x or y become same in both equations so that we could add or subtract them to cancel one of the term either x or y.

So, given equations are :

5x - 12 = 3

-20x + 14 y = 13

See we have 5x in first equation and -20x in second equation.

So, we try to change 5x into 20 x by multiplying it with 4, both of the equations will have 20 x in common

Lets multiply 4 in first equation

4 * (5x-12y) = 4 * 3

20x - 48y = 12

Now both equations could be added and 20 x will be cancelled out and we could easily find the value of y then solve for x.

So, Justin should try to change 5 so that it will be cancels, so option B  :  Answer

Hope it will help :)


3 0
3 years ago
Explain why animals can hear sounds humans can't
DedPeter [7]
Better hearing and better sound censory

i think anyways
7 0
2 years ago
Read 2 more answers
Help plz I’ll give brainliest and I’m struggling with this problem
hodyreva [135]

The line is starting from right side and goes thorough left .

Means

  • Its starts from 1st Quadrant and goes to 3rd Quadrant.(+ve to -ve)
  • Y is infinite

Hence

The solution is

\\ \sf\longmapsto (0,\infty]

6 0
2 years ago
Find an equation of the line passing through the point (2, -3) and has slope -4. Then rewrite your linear equation in the slope-
Tresset [83]

Answer:

y=-4x+5

Step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

-3. -3

y=-4x+5

8 0
3 years ago
How can i differentiate this equation?
Dmitry_Shevchenko [17]

\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}


\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}


\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}

8 0
3 years ago
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