It doesn't matter what's between it as long as it is within that range, if that makes any sense.
1.25 isn't.
1.75 isn't.
1.83 isn't.
1.625 would be your answer. :)
The answer to your question that you’re trying to figure out is [3,5]
80x3/8=10 common factor. 10x5. And 10x3
50/30
30 boys
50 girls
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
The answer is 216.
https://photomath.net/s/YLLqQX
