Question

A car came to a stop from a speed of 28 m/s in a time of 2.1 seconds. What

Answer 1

Answer: $-13.33 m/s^{2}$

Step-by-step explanation:

We can solve this problem with the following equation:

$a=\frac{V-V_{o}}{\Delta t}$

Where:

$a$ is the acceleration of the car

$V_{o}=28 m/s$ is the initial velocity of the car

$V=0 m/s$ is the final velocity of the car

$\Delta t=2.1 s$ Is the time in which the car came to a stop

Solving:

$a=\frac{0 m/s - 28 m/s}{2.1 s}$

$a=-13.33 m/s^{2}$ This is the car's acceleration, note the negative sign indicates the car was decreasing its velocity before coming to a stop.

Answer 2

The answer is : -13.3 m/s^2