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VashaNatasha [74]
3 years ago
12

A car came to a stop from a speed of 28 m/s in a time of 2.1 seconds. What

Mathematics
2 answers:
Arlecino [84]3 years ago
7 0

Answer: -13.33 m/s^{2}

Step-by-step explanation:

We can solve this problem with the following equation:

a=\frac{V-V_{o}}{\Delta t}

Where:

a is the acceleration of the car

V_{o}=28 m/s is the initial velocity of the car

V=0 m/s is the final velocity of the car

\Delta t=2.1 s Is the time in which the car came to a stop

Solving:

a=\frac{0 m/s - 28 m/s}{2.1 s}

a=-13.33 m/s^{2} This is the car's acceleration, note the negative sign indicates the car was decreasing its velocity before coming to a stop.

I am Lyosha [343]3 years ago
6 0

The answer is : -13.3 m/s^2

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