Answer:
I agree with daniel
Step-by-step explanation:
Given the area of a rectangle expressed as;
A(x) = 2x²+10x+12
On factorizing;
A(x) = 2x²+6x+4x+12
A(x) = 2x(x+3)+4(x+3)
A(x) = (x+3)(2x+4)
since A(x) = l(x)w(x)
Hence the legnth and width of the rectangle are 2x+4 and x+3.
Also A(x) = 2x²+6x+4x+12 can be factorized as;
A(x) = 2x²+4x+6x+12
A(x) = 2x(x+2) + 6(x+2)
A(x) = 2x+6(x+2)
Therefore I agree with Daniel. The factor differs due to the difference in arrangement of 4x and 6x in the expression. Precedence of values affects the final factors
Step-by-step explanation:
C= 72..............
C3=216
C=216
3
C = 72
Thanks
Let's solve for x.
−x+9y=−5
Step 1: Add -9y to both sides.
−x+9y+−9y=−5+−9y
−x=−9y−5
Step 2: Divide both sides by -1.
−x ÷ −1 = −9y−5 ÷ −1
x=9y+5
THE ANSWER FOR THE OTHER EQUATION: (x-5y=1)
Let's solve for x.
x−5y=1
Step 1: Add 5y to both sides.
x−5y+5y=1+5y
x=5y+1
Answer:
x=5y+1
I hope this helped I was a little confused on what your problem meant...so if this is not what you asked for just lmk so I can fix it for you :)
Answer:
m= rise/run = y2-y1/x2-x1
<span><span>1.
</span>The music hall has 20 boxes :
=> on thurs 2/5 were occupied
=> on friday 2/4 were occupied
=> and on saturday 8/10 were occupied.
Let’s find out which day has the most occupied space of the music hall.
2/5 + 2/4 + 8/10 = 6/20 + 7/20 + 10/20
Thurs 2/5 were occupied
=> 6/20 = 0.3
=> 20 * 0.3 = 6 boxes
Friday 2/4 were occupied
=> 7/20 = 0.35
=> 20 * 0.35 = 7 boxes
Saturday 8/10 were occupied.
=> 10/20 = 0.5
=> 20 * .5 = 10 boxes
Thus, during Saturday has the most number of occupied boxes.</span>
