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timofeeve [1]
3 years ago
5

According to the fundamental theorem of algebra, how many zeros does the polynomial below have?

Mathematics
2 answers:
madam [21]3 years ago
7 0

Answer: 3!

Step-by-step explanation:

A P E X

Oxana [17]3 years ago
6 0
It has 3 zeros, because its a polynomial of degree 3.
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What is the slope–intercept form of the equation 4x − 2y = 9?
adelina 88 [10]
Hey there! :D

Slope intercept form: y=mx+b

4x-2y=9

Add 2y to the other side. 

4x=9+2y

Subtract 9 on both sides.

4x-9=2y

Flip the equation over. 

2y=4x-9 <== slope intercept form 

I hope this helps!
~kaikers
5 0
3 years ago
9 and 5 twelves, minus 6 and 7 twelves
mash [69]

Answer:

2 5/6

Step-by-step explanation:

9 5/12 - 6 7/12

We will need to borrow from the 9

8 12/12 + 5/12 - 6  7/12

8 17/12 - 6 7/12

(8-6) + (17/12 -7/12)

2 10/12

This simplifies.  Divide the top and bottom of the fraction by 2

2 5/6

5 0
3 years ago
Help thanks 7.04 love u guys​
Ugo [173]

Answer:

D. -\frac{3}{4}

Step-by-step explanation:

The given equation is

4y=8x-3

When we divide through by 4 we get;

y=2x-\frac{3}{4}

Comparing to

y=mx+c,

The y-intercept is -\frac{3}{4}

The corrrect choice is D.

3 0
3 years ago
Read 2 more answers
How would you simplify the expression represented by the diagram below? Four figures. The first consists of 4 squares each label
Sergeu [11.5K]

Answer:

6 x 3c

Step-by-step explanation:

6 0
3 years ago
Kamal wrote the augmented matrix below to represent a system of equations
ra1l [238]

Consider the operation is R_2\to -3R_2.

Given:

The augmented matrix below represents a system of equations.

\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]

To find:

Matrix results from the operation R_2\to -3R_2.

Step-by-step explanation:

We have,

\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]

After applying R_2\to -3R_2, we get

\left[\left.\begin{matrix}1&0&1\\-3(1)&-3(3)&-3(-1)\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-3(-9)\\-2\end{matrix}\right]

\left[\left.\begin{matrix}1&0&1\\-3&-9&3\\3&2&0\end{matrix}\right|\begin{matrix}-1\\27\\-2\end{matrix}\right]

Therefore, the correct option is A.

3 0
3 years ago
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