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3 years ago

The last term in the expansion of the binomial (3x+6)^3

Mathematics

1 answer:

Crank3 years ago

7 0

=(3x+6)^3
= 27x^3+216
The last term is 216.

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Find all angles, 0º < 0 < 360°, that solve the following equation. cos 0 = 1

Annette [7]

Tbh not completely sure but I think its 180 .

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3 years ago

Which type of table shows the probability of an event occurring?

kirza4 [7]

Answer:

A. frequency table

Step-by-step explanation:

In probability, which is the study of events which may or may not occur, the frequency distribution table shows the numerical value which is assigned to the likelihood of an event and the probability of occurrence of the event.

8 0

2 years ago

QUESTION 3 I [12] A student must answer a multiple-choice question with five possible answers. He knows the correct answer with

wel

The probability that the student does not know the answer but he randomly guesses it is 0.146025

<h3>How to solve for the probability of having a correct guess</h3>

The question has only one right answer out of 5 choices.

Probability he answers incorrectly:

1 - 0.55 * 4/5

= 0.45 * 0.8

= 0.36

Probability he does not know answer but answers the question correctly

$\frac{(1-0.55)\frac{1}{5} }{0.55+(1-0.55)\frac{1}{5} }$

= 0.09/0.55+0.09

= 0.140625

Read more on probability here: brainly.com/question/24756209

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2 years ago

Are there more than one way to solve problems? Provide an example, either in math class

madreJ [45]

Answer:

try doing it on your own so you can get better at it

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3 years ago

The lifetimes of a certain type of light bulbs follow a normal distribution. If approximately 2.5% of the bulbs have lives excee

spin [16.1K]

Answer:

Mean = 339 hours

Standard deviation = 54 hours

Step-by-step explanation:

We are given that approximately 2.5% of the bulbs have lives exceeding 445 hours

So,P(x>445) = 0.025

P(x<445) =1- 0.025 =0.975

z value for 0.975 is 1.96

Formula : $z=\frac{x-\mu}{\sigma}$

So, $1.96=\frac{445-\mu}{\sigma}$

$1.96 \sigma =445-\mu$ --A

Now we are given that approximately 16% have lives exceeding 393 hours,

So,P(x>393) = 0.16

P(x<393) =1- 0.16 =0.84

z value for 0.84 is 1

Formula : $z=\frac{x-\mu}{\sigma}$

So, $1=\frac{393-\mu}{\sigma}$

$1 \sigma =393-\mu$ ---B

Solve A and B

Substitute the value of $\sigma$ from B in A

$1.96 (393 -\mu) =445-\mu$

$770.28 -1.96\mu=445-\mu$

$770.28 -445=1.96\mu-\mu$

$325.28=0.96\mu$

$\frac{325.28}{0.96}=\mu$

$338.83=\mu$

Substitute the value in B

$\sigma =393-338.83$

$\sigma =54.17$

So, mean = 339 hours

Standard deviation = 54 hours

5 0

3 years ago