Answer:
3.777
Step-by-step explanation:
Answer:
12 hours :)
Step-by-step explanation:
I can’t answer it doesn’t have enough information
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
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Answer:
The velocity of the particle will be zero for t = 1.47 sec .
Step-by-step explanation:
Given equation:
a(t)=t+sin(t)
lets integrate it with respect to time,
∫ a(t) dt = ∫(t+sin(t)) dt
⇒ v(t) =
- cos(t) +c
At, t=0, v= -2 so,
⇒ -2 = 0 - 1 +c
⇒ c= -1
Hence,
v(t) =
- cos(t) -1
for the velocity to be zero,
0 =
- cos(t) -1
⇒ t = 1.47 sec (taking only positive value)
So at 1.47 sec the velocity of particle will be zero.