I believe the correct answer to this question is 42 and 288. If im not wrong.
Answer:
43.60°
Step-by-step explanation:
We can solve the triangle using the trigonometrical ratios which may be expressed in the form SOA CAH TOA Where,
Sin Ф = opposite side/hypotenuses side
Cosine Ф = adjacent side/hypotenuses side
Tangent Ф = opposite side/adjacent side
The hypotenuse is the side facing the right angle while the opposite is the side facing the given angle.
Considering triangle ΔDEF, where ∠F=90°, FE = 21, DF = 20, and ED = 29
As such, with respect to angle E, ED is the hypotenuse, DF is the opposite side and FE is the adjacent side
Cosine ∠E = 21/29
∠E = cos-1 0.724137931
∠E = 43.60° to the nearest hundredth
Hello! The interquartile range would be 5°
You must subtract Quartile one from quartile 3 to find iqr
Answer:
Step-by-step explanation:
Given
Required
Evaluate
is equivalent to :
Hence:
Law of cosines:
a^2 = b^2 + c^2 -2 *b*c*coa(a)
a^2 = 60.5^2 + 257^2 - 2*60.5*257*cos(31)
a^2 = 3660.25 + 66049 - 2 *60.5 * 257 * 0.857167
a^2 = 3660.25 + 66049 - 26655.33
a^2 = 43053.92
a = SQRT(43053.92)
a = 207.49 = 207.5 feet.
The answer is A.
