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Wewaii [24]
3 years ago
10

Double w then raise the result to the 4th power

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

2w to the 4 power (as an exponent)

Step-by-step explanation:

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Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 16 + 2x − x^2, [0, 5]
RSB [31]

Answer:

<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>

Step-by-step explanation:

To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.

at x = 0;

f(0) =  16 + 2(0) − 0²

f(0) = 16

at the other end point i.e at x = 5;

f(5) =  16 + 2(5) − 5²

f(5) = 16 + 10-25

f(5)= 26-25

f(5) = 1

The absolute minimum value is 1  and  occurs at x  = 5

The absolute maximum value is 16 and  occurs at x  = 0

5 0
3 years ago
Write the first four terms of the sequence defined by each of the following recursive formulas.
Dafna11 [192]

Answer:

First equation : 3, 0, -3, -6

Second equation : 2, 2.5, 3, 3.5

Step-by-step explanation:

What the first equation is basically saying is subtract 3 each time.

What the second equation is basically saying is add 0.5 each time.

Then we just add/subtract to find the first four terms.

3 0
3 years ago
Read 2 more answers
Using PYTHAGORAS THEOREM answer the question A vertical pillar ab bent at c at a height of 2.4m and its upper end b touches the
Alisiya [41]

Answer:

  5.4 m

Step-by-step explanation:

The Pythagorean theorem tells you the relationship between the various lengths is ...

  cd² = ac² +ad²

  cd² = (2.4 m)² + (1.8 m)² = 9.00 m²

  cd = √(9.00 m²) = 3.0 m

Since cd = cb and ab = ac+cb, we have ...

  ab = 2.4 m + 3.0 m = 5.4 m

_____

You may recognize this as a 3-4-5 right triangle with a scale factor of 0.6. We are asked for the sum of the lengths of the "4" and "5" legs, which is ...

  0.6·(4+5) = 5.4

7 0
3 years ago
Which luncuon escribes ud yait:
anastassius [24]

Answer:

it is 27

Step-by-step explanation:

5 0
3 years ago
Find the approximate area between the curve f(x) = -4x² + 32x and on the x-axis on the interval [0,8] using 4 rectangles. Use th
Doss [256]

Split up the interval [0, 8] into 4 equally spaced subintervals:

[0, 2], [2, 4], [4, 6], [6, 8]

Take the right endpoints, which form the arithmetic sequence

r_i=2+\dfrac{8-0}4(i-1)=2i

where 1 ≤ <em>i</em> ≤ 4.

Find the values of the function at these endpoints:

f(r_i)=-4{r_i}^2+32r_i=-16i^2+64i

The area is given approximately by the Riemann sum,

\displaystyle\int_0^8f(x)\,\mathrm dx\approx\sum_{i=1}^4f(r_i)\Delta x_i

where \Delta x_i=\frac{8-0}4=2; so the area is approximately

\displaystyle2\sum_{i=1}^4(-16i^2+64i)=-32\sum_{i=1}^4i^2+128\sum_{i=1}^4i=-32\cdot\frac{4\cdot5\cdot9}6+128\cdot\frac{4\cdot5}2=\boxed{320}

where we use the formulas,

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6

6 0
3 years ago
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