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Dahasolnce [82]
3 years ago
14

#1. Find the circumference of the following circle: *

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

40.82

Step-by-step explanation:

I got this answer by multiplying the diameter by pi.(3.14 was used for pi)

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Point c is located in which quadrant?​
Murrr4er [49]

Answer 4

Step-by-step explanation:

Top right 1

Top left 2

Bottom left 3

bottom right 4

7 0
3 years ago
Read 2 more answers
Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and cos ∠X = 2.5 over 5 and 59 hundredths. Triangles XYZ
adell [148]

Dilation involves changing the size of a shape

<h3>How to determine the relationship between the trigonometry ratios</h3>

From the question, we understand that:

The dilation of triangle XYZ gives triangle ACB

This means that, the following are corresponding points

  • Points X and A
  • Points Y and C
  • Points Z and B

The above means that:

The relationships between the trigonometry ratios of both triangles are:

cos(X) = cos(A), cos(Y) = cos(C) and cos(Z) = cos(B)

<h3>How to determine the measures of segments AC and AB</h3>

In (a), segments XY and XZ corresponds to the segments AC and AB

So, the product of the lengths of XY and XZ and the scale factor will result in the lengths of AC and AB,

i.e.

AC = 2 * XY and AB = 2 * XZ

Read more about dilation at:

brainly.com/question/26332230

5 0
2 years ago
Two of the sides of a triangle are 7 inches
igomit [66]

Answer:

11 inches

Step-by-step explanation:

7^2+8^2=c^2

49+64=c^2

113=c^2

square root both side

c=10.63014581

round up and get c=11

hope this helped :)

8 0
3 years ago
The sum of the measures of the interior angles of a polygon with n sides is
Andrew [12]

Answer:

B

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = (n - 2) × 180° ← n is the number of sides

8 0
3 years ago
Grace can read 840 words in 7 minutes. At that rate, how many words can she read in one hour
slega [8]

Answer:

5740

Step-by-step explanation:

7 0
3 years ago
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