2 years ago

Suppose Ken has 25 coins and nickels and dimes only and has a total of a $1.65 how many of each coin does he have?

1 answer:

6 0

$x-\ number\ of\ nickels\\
y-\ number\ of\ dimes\\\\
x+y=25 \ \ \ | x=25-y\\
0.05x+0.1y=1.65\\\\
0.05(25-y)+0.1y=1.65\\\\
1.25-0.05y+0.1y=1.65\\\\
1.25+0.05y=1.65\ \ \ | subtract\ 1.25\\\\
0.05y=0.4\ \ \ \ \ | divide\ by\ 0.05\\\\
y=8\\\\
x=25-8=17\\\\
There\ are\ 17 \ nickels\ and\ 8\ dimes.
$

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