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aliina [53]
4 years ago
14

Solve for n: 2(n+5) = -2

Mathematics
2 answers:
xz_007 [3.2K]4 years ago
7 0
The answer for n is -6 because if you replace -6 for n then times it by 2 will give you -12 +10=-2. then subtract -12 from 10 then you get negative 2

Temka [501]4 years ago
3 0
The answer should be n= -6
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3 years ago
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What is the nth term of the sequence -2 -8 -18 -32 -50
andreev551 [17]

Answer:

-2n²

Step-by-step explanation:

Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
T_{n} = an^{2}  +bn +c

To find the value of a we just divide second difference ( -4 ) by 2:

  • a = \frac{-4}{2}= -2

Now we have:

  • T_{n}= -2n^{2}  +bn+c

Substitute n_{1} and n_{2} into the equation above:

  • T_{1} = -2(1)^{2}  +b(1) +c
  • T_{2} = -2(2)^{2}  +b(2)+c

Since T_{1} = -2 and T_{2} = -8 , after simplification we have:

  • b +c =0
  • 2b+c=0

The solution of this system is:

  • b=0, c =0

The general term is :

T_{n} = -2n^{2}

6 0
2 years ago
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
The price of an Item has been reduced by $5.09. The new sale price is $41.03. What was the original price?
Orlov [11]

Answer:

the original price was $46.12

Step-by-step explanation:

if you add 5 back to that number.

8 0
2 years ago
What is 6/10 + 9/10 in simplest form?
Sonbull [250]

Answer: 3/2

Step-by-step explanation:

<u>Given</u>

6/10 + 9/10

<u>Add the numerator together</u>

= (6 + 9) / 10

<u>Simplify by addition</u>

= 15 / 10

<u>Simplify to simplest form by division</u>

= (15 ÷ 5) / (10 ÷ 5)

= 3 / 2

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
Read 2 more answers
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