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UkoKoshka [18]
4 years ago
6

What is 5/12 times 6 in multiply fractions with whole numbers

Mathematics
1 answer:
KiRa [710]4 years ago
3 0
5/12*6  =5/12*6/1 crosscancle you get 5/2 the you get 2 1/2
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HELP ASAPPPPP<br> When graphing the inequality y &gt; -4x + 6, what type of line should be graphed?
melomori [17]

Answer:

A dashed line

Step-by-step explanation:

The end points of the line for the inequality would not be included since y is only greater, not greater than or equal to.

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4 years ago
What is the equation of the quadratic function graphed below?
Hitman42 [59]

Answer:

y = -3(x + 1)² + 9

Step-by-step explanation:

y = a(x - h)² + k, where (h, k) is the vertex

The vertex of the quadratic function is (-1, 9)

The only equation listed that has a vertex at (-1, 9) is:

y = -3(x + 1)² + 9

5 0
4 years ago
Parallel lines t and u are cut by two transversals, r and s, which intersect line u at the same point.
Bezzdna [24]

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3 years ago
Read 2 more answers
HELP pls!!
Rudiy27
<h3>Answer: Choice B) x = 65, y = 10</h3>

====================================================

Work Shown:

The upper pair of angles 60 degrees and (2x-y) degrees are supplementary angles. This is because of the parallel lines. Note how they are same side interior angles. Therefore, (2x-y) and 60 combine to 180 degrees like so

(2x-y)+60 = 180

2x-y = 180-60 ... subtract 60 from both sides

2x-y = 120 ... call this equation 1

-------

Similarly, (2x+y) and 40 also combine to 180

(2x+y) + 40 = 180

2x+y = 180-40 ... subtract 40 from both sides

2x+y = 140 ... call this equation 2

------

Line up equation 1 and equation 2. Then add straight down

\ \ \  2x-y = 120\\+ 2x+y = 140\\\hrule\\\\\\ \ \ \ 4x+0y = 260\\\\

That becomes 4x = 260 which solves to x = 65 when you divide both sides by 4.

------

If x = 65, then,

2x-y = 120

2(65)-y = 120

130 - y = 120

-y = 120-130

-y = -10

y = 10

or

2x+y = 140

2(65)+y = 140

130+y = 140

y = 140-130

y = 10

----------

Either way end up with x = 65 and y = 10

4 0
3 years ago
What is a correct equation for the line passing through the point (-2,1) and having slope m=1/2
frez [133]

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

We ahve the slope m = 1/2 and the point (-2, 1). Substitute:

y-1=\dfrac{1}{2}(x-(-2))

y-1=\dfrac{1}{2}(x+2) - point-slope form

Covert to the slope-intercept form (y = mx + b):

y-1=\dfrac{1}{2}(x+2)          <em>use the distributive property</em>

y-1=\dfrac{1}{2}x+1          <em>add 1 to both sides</em>

y=\dfrac{1}{2}x+2   - slope-intercept form

Convert to the standard form (Ax + By = C):

y=\dfrac{1}{2}x+2     <em>multiply both sides by 2</em>

2y=x+4        <em>subtract x from both sides</em>

-x+2y=4         <em>change the signs</em>

x-2y=-4   -  standard form

Convert to the general form (Ax+By+C=0):

x-2y=-4        <em>add 4 to both sides</em>

x-2y+4=0   - general form

5 0
4 years ago
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