Let f(x) = ax³ + 9x² + 4x – 10
g(x) = 0⇒x - 3 = 0
⇒ x = 0 + 3
⇒ x = 3
On dividing f(x) by x - 3, it leaves a remainder 5.
Now keeping, f(3) = 5
⇒a(3)³ + 9(3)² + 4(3) - 10 = 5
⇒ a × 27 + 9 × 9 + 4 × 3 - 10 = 5
⇒ 27a + 81 + 12 - 10 = 5
⇒ 81 + 12 - 10 - 5 = 27a
⇒ 81 + 12 - 15 = 27a
⇒ 93 - 15 = 27a
⇒ 78 = 27a
⇒ a = 27/78
⇒ a = 0.3461
Answer:
630
Step-by-step explanation:
Given that:
First flip = 72 coins
For each coin which is a head, you roll = 5, six-sided dice
Thus, the expected sum on a single six-sided dice =
=
= 3.5
Thus, the expected sum on the five six-sided dice = 5 × 3.5 = 17.5
However, for a single flip :
The expected sum = P(heads) × expected sum on 5 dice + P(tails) × expected sum on 0 dice.
Expected sum =
Expected sum = 8.75
Hence, the expected total score from this game = 72 × 8.75 = 630
Base on my calculation and the simplification of the form and finding its 4th power of the x+2y, i came up with a solution and finally found an answer of B. 448x^5y^3, I hope i answer your questions directly and please feel free to ask for more and ask for clarifications
(B) I am glad to help you thank you