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saveliy_v [14]
3 years ago
13

Write an equation, in slope-intercept form, that passes through point (-6,5) with slope 2.

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer:

y=2x+17

Step-by-step explanation:

There is enough information to make a point-slope form of the equation and then convert it into slope intercept form.

Point Slope is: y-y_1=m(x-x_1)

'm' - slope

(x1,y1) - point

We are given the point (-6,5) and a slope of 2.

y-y_1=m(x-x_1) \rightarrow \boxed{y-5=2(x+6)}

Convert the equation into slope intercept form:

y-5=2(x+6)

y-5=2x+12\leftarrow \text{Distribute} \\y-5+5=2x+12+5\leftarrow \text{Addition Property of Equality} \\\boxed{y=2x+17}

The equation should be y=2x+17.

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